Quote:
Originally Posted by PrimordialAA
sample sizes FTL...
So many people have said this....
He has a binomial variable with p = 0.319 and n = 974.
The standard deviation is sqrt(np(1-p)) = 14.54
The expected value is np = 310.85
His observed result was 211.
This is (310.85 - 211) / 14.54 = 6.86 standard deviations away from the mean, which is extremely significant - a worse result occurs less than 10^-11 of the time, (using the normal approximation, which ought to be fine here as the data has low skew) i.e. thousands of times less likely than winning the lottery.
His 974 hand sample is MORE than enough to conclude that something is not right in the shuffle, if his methodology was right.
You do not need very many hands at all to test binomial statistics with p's relatively close to 0.5.
Last edited by Pyromantha; 12-12-2009 at 06:10 AM.