What we really want to know is ...

Is the derivative on 'crazy' positive or negative?

Judging by this thread and the thread five years ago, is OP more crazy now or then?

They are, but I disclosed them to show what can happen in an array.

Information for you, we are born into an insane world, one that puts a value on things by subjective means.

A diamond for example has a subjective value.

It is not me who is insane, it is those who believe everything they were taught.

He is the exact same person. Not a thing changed. I admit I am surprised some people engaged him so much this time that were in that mess a few years ago, but I cave into that behavior at times as well, so ?/? can judge.

How do you think it should look in an array if it was truly random?
How does it differ between a computer generated deck and a hand shuffled one?

Answer my infinite deck probability question plz

Posts ITT since this exit rant:
52

Omg.

Come back op. I want to learn more about physics impacting the array of virtual cards.

LOL, I went into his history to do a quick count to see how many of those 52 were his, and realized that's the number you were giving us. Wow.

How has this thread not been moved from Probability to Psychology?

LOL, seriously.

I had to have a think about the answer to this, sorry for the late response.


The answer is ? / t

As it seems there is only a few of you are close to understanding, let us look at the intricate details of the notion and begin with helping everyone to understand what a R² coordinate space is.

https://en.wikipedia.org/wiki/Real_coordinate_space


In the right in this link you can see the sort of array I am referring too.


Anybody not understand an array?


The elements of the array are playing cards, all the rows of integer x have 52 individual constant elements


integer x={1,2,3,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,52 }

{} denotes a set

All the columns of y have 52 elements and y is formed by the position randomisation of all integer x.

..y
{1,2,3,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,52}
{1,2,3,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,52}
{1,2,3,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,52}
{1,2,3,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,52}x
.
.
.
.
52

ok so far? anyone not understand?


Where [a] equals any constant value from x we can say P [a]/x = 1 /52 for all [a]/x

Where [a] equals any constant value from y we can say P [a]/y = 1 /52 for all [a]/y


For any random pick of any [a] from the x,y array, being any specific value.

Any one disagree?

Where [b] equals a specific denominator such as an ace we can express


∑[b]/x,y=208/2704

P [b]/x,y = 208/2704 For All [b]/x,y


For any random pick of any [b] from the x,y array, being any specific denominator.

Question 1 - In a R² coordinate space where x=52 and y=52 , if we were to random pick from an undisclosed x,y array, one individual element , does any one disagree and think anything other than your choice is out of 2704 elements?

i) The probability of there being one c in Z is about 0.18%. The probability of there being more than one c in Z is about 0.02%. Therefore, there will be on average 0.2 c's in Z.

ii) Same as above - there will be on average 0.2 7's in Z.

iii) I don't know what the question means.

E&OE

iii) What is the total amount of Z?

How many boxes are there in total to pick from.

I think this thread killed Stephen Hawking.

0.

We have three boxes. One of the boxes has a prize.

We let Person A pick two of the boxes.

A then turns to Person B and lets him pick one of those two boxes.

We all agree that A had a 2 in 3 chance of picking a box with a prize.

We also know that 2/3 of the time, Person B will have a 1/2 chance of getting a prize, and 1/3 of the time they have a 0% chance.

The OP begins his thought process at the point where Person B selects the box, and expresses B’s chances at ?/2, since the content of the two boxes is an unknown.

The rest of us begin the process with the initial three boxes, and understand that the combination of B’s odds can be calculated as 1/3.

And on we go.

I just skimmed this whole thread sitting in the back of a taxi. Does this whole **** show boil down to OP not being able to understand that if you flip a coin 3 times you would expect to get 1.5 heads even though you can't end up with that result?

In part. He doesn't understand the most basic math and when you say he's an idiot he tells you he is sorry that you have poor math.

What he is most upset and furry mad about is that when you make a 52x52 card matrix, shuffle the horizontals and pick a card from the y-axis it's possible to have more than 1 of the same card, therefor he thinks it changes the 1/52 odds.

But his answer to the problem is that we don't understand it. None of us, none of mathematicians in the world. We're all wrong, he is right.

Got it. Thanks for saving me 5 hours. How did the thread last this long?

Wait...does he really think that every "column" of a 52x52 matrix (if I'm understanding correctly the "rows" are the order of cards in a single shuffled deck) should contain exactly 1 of each card? Like a column should be a complete deck? If so I don't know what to say.

The x-axis is shuffled and then you have 52 rows of decks (shuffled). Then you're supposed to pick one card in the y-axis (which can have up to 52 of the same cards) and he believes the odds of picking a specific card change.

I guess I get it. Not entirely sure I do but am 100% sure I don't need further clarification. Thx.

(still subscribing to see the where the exciting "time" teaser takes us)