But its 1/52 and not 1/13 by time we have 52 mixed cards in each box because we can't know how many aces went into each box. But yes I now believe you see the Paradox, the reason everyone misses the point is because Paradox's are really hard to spot, but once it can be expressed in simplicity terms, it is easy to see.

edit - ''Is it possible that nobody has already explained it thusly:

Number the decks from 1 to 52. Number small boxes from 1 to 52. Select one card from deck 1 and put it in box 1. Same for deck 2 and box 2. And so on.

What are the chances that the card in, say Box 15 is any specific value? Obviously its 1/52/Since it is a randomly selected card from deck 15. But this would be true for any of those 52 boxes. So the answer is always going to be 1/52.

Both the answer and the explanation is so obvious it makes me wonder if I misunderstood the question or missed someone else answering it this way.''

Your original decks 1 in 52

Your cards in your boxes 1 of 52


Paradox.

6th post of thread: And later: People here apparently didn't click what Lego linked to in an early post. OP is the same person from this thread who couldn't be (or pretended not to be) convinced by real-life experiments. From that thread: Which brings us to the most pertinent post: Oh and thanks whosnext! Hope your Thanksgiving was nice too.

Are you trying to say there is no Paradox? if this is the case then you are clearly wrong sir.

You getting a math problem wrong isn't a paradox.

I am not getting the maths wrong, you are not considering two independent events running simultaneously.


Ok, let's try it this way.

We have deck 1 we call this event (A)


We have a second deck, we will call this event (B)


We randomly shuffle event (A)

We randomly shuffle event (B)

I ask you to take the top card from event (A)

What is the chance the card you have picked is any ace?

What is the chance the card you have is any 1 of the 52 variants?

Please help my understanding. Let's try it this way.

1. A deck is sitting on a table in front of you. You slide the top card off the deck and place it on the table. What is the chance this card is an ace?

2. There are 52 decks sitting on a table in front of you. You randomly choose one of the decks and and remove the other 51 decks from the table. You leave the room taking those 51 decks with you. Someone else comes into the room without any knowledge of the you or the decks you removed. He slides the top card off the remaining deck and places it on the table. What is the chance this card is an ace?

If you answer my questions I will guide you to answering it yourself.

I will answer your questions.

Ok thank you, let's try it this way.

We have deck 1


We have a second deck, we will call this deck 2


We randomly shuffle deck 1

We randomly shuffle deck 2

I ask you to take the top card from deck 1

What is the chance the top card is any ace?

What is the chance that the top card is one of any value of the 52 known values ?

1. 52 cards, 4 aces, chance is 4 out of 52

2. The way the question reads the answer is 1 out of 1, the top card will be one of the known values. If you are asking about a specific card, the answer is 1 out of 52.

Ok thank you, let's try it this way.

We have deck 1


We have a second deck, we will call this deck 2


We randomly shuffle deck 1

We randomly shuffle deck 2

I ask you to take the top card from deck 2

What is the chance the top card is any ace?

What is the chance that the top card is any specific value of the 52 known values ?

1. 52 cards, 4 aces, chance is 4 out of 52

2. a specific card, the answer is 1 out of 52.

Ok thank you, let's try it this way.

We have deck 1


We have a second deck, we will call this deck 2


We randomly shuffle deck 1

We randomly shuffle deck 2


I ask you to take the top card from deck 1

I ask you to take the top card from deck 2

What is the chance the top card of deck 1 is the exact same value as the top card of deck 2?

1 out of 52

Ok thank you, let's try it this way.

We now have 100 decks

numbered 1-100

We individually randomly shuffle all 100 deck's

I ask you to take the top card from each deck

What is the chance of any individual card being any specific variant?

What is the chance any individual card is an ace?

1 out of 52

4 out of 52

Ok thank you, let's try it this way.

We now have 100 decks

numbered 1-100

We individually randomly shuffle all 100 deck's

I ask you to take the top card from each deck

What is the chance of any individual card is the same value card as another individual card?

Can you clarify, do you mean there is exactly one match for any one of the cards, or do you mean there is at least one match for any one of the cards?

You have 100 top cards, each card has a 1/52 chance to be any specific card, 100 cards all individually have a 1/52 of being the same value card

I.e deck 1 /top card, has a 1/52 chance to be a 7d

I.e deck 21/top card also has a 1/52 chance to be 7d

I.e deck 87/top card also has a 1/52 chance to be 7d.

Ok thank you, let's try it this way.

We now have 100 decks

numbered 1-100

We individually randomly shuffle all 100 deck's

I ask you to take the top card from each deck

What is the chance of any individual card is the same value card as another individual card? 100 cards all with 1/52 chance to be any specific variant , all independently equal of 1/52 to be the same value as the next card.

Do you agree with this maths?

It's been a long time since I was in a statistics class and I don't use it much in my day-to-day activities, but I would imagine that the chances of a card being duplicated would be quite high. Far more than 1 in 52 - you get 99 chances to do it!

We are not talking likely or unlikely, we are talking probable.

Earlier you agreed -



Ok thank you, let's try it this way.

We have deck 1


We have a second deck, we will call this deck 2


We randomly shuffle deck 1

We randomly shuffle deck 2


I ask you to take the top card from deck 1

I ask you to take the top card from deck 2

What is the chance the top card of deck 1 is the exact same value as the top card of deck 2?
Today 02:12 PM
Didace
Re: A strange question of values.
1. 52 cards, 4 aces, chance is 4 out of 52

2. a specific card, the answer is 1 out of 52.
Today 01:59 PM


I ask again ,

We now have 100 decks

numbered 1-100

We individually randomly shuffle all 100 deck's

I ask you to take the top card from each deck

What is the chance of any individual card is the same value card as another individual card?

100%

Well yes , as well, maybe I need to re-word this question. I was looking for 1/52 but yes 100% as well now I have read my own question differently than I intended it to mean.

Well, one way to figure that would be to determine the chance that one of the cards did not have a match and then the answer would be whatever was left over. So, 1-(chance of a lone card). But as I said, this type of formula is buried deep in old unused memories so I don't have it at hand.

I guess the answer is pretty high, maybe as much as 80%. Someone with a better memory than me would need to provide the formula and then I can do the math.