Open Side Menu Go to the Top
Register
Blind Math Blind Math

02-26-2015 , 10:39 AM
Hey guys, I hope I dont say anything too stupid here, I was trying to figure out how much bb/100 winrate is acceptable at BB and at SB

If we are 6 handed, in 100 hands we see 16,66 orbits. 100/6

In each orbit, if we just fold our blinds, we would than loose:

BB - 16,66bb/100hands
SB - 8,3bbs/100 hands

Total around 25bbs/100 that we loose if we choose to fold all blinds no matter what.
Does this mean, that if we have a winrate lower than -16.66bbs / 100 at BB and -8.33bb / 100 at SB we are just better off not playing that position at all?

Again, I hope this is not a ******ed question.
Blind Math Quote
02-26-2015 , 10:58 AM
You don't calculate winrate by position this way.

You take all the hands you play from one position and calculate the winrate. You lose 100bb/100 if you fold your bb and 50bb/100 if you fold your sb.
Blind Math Quote
02-26-2015 , 11:17 AM
Ohhhhhhhh, I see

So when PT says 10bb/100h from the SB, it means from 100 hands played exclusively at SB.

Alright. So it kinda ******ed what I was thinking, but I still wanna know:

Whats an acceptable range of winrate from each of theses positions? Is it possible to break even at SB?
Blind Math Quote

      
m