// ==UserScript==
// @name       Always Open External Links In New Tab
// @namespace  http://use.i.E.your.homepage/
// @version    0.1
// @description  enter something useful
// @match      *://*/*
// @copyright  2012+, You
// ==/UserScript==

var nodeList = document.getElementsByTagName("a");
for (var i=0; i<nodeList.length; i++) {
    var link = nodeList[i];
    if (link.href.indexOf(location.hostname) == -1)
        link.target = "_blank";
}

[foo, bar, foo, x, y, x]

[foo, bar, , x, y, ]

if ($array[$j]) {
// do something
}

To query for elements based on css selectors, instead of:

$('.foo .bar')
to get a single element, do:

document.querySelector('.foo .bar')
and to get a list of elements do:

document.querySelectorAll('.foo .bar')

To set css styles, instead of:

$(element).css(name, value)
you can do:

element.style[name] = value
This should work in all browsers but note that you'll sometimes need to attach the element to the document body before its style property will be set. You can if (!element.style) element.style = {} to get around that.

$a = array('foo', 'bar', 'foo', 'x', 'y', 'x');
$b = array_values(array_unique($a));
var_dump($b);

$result = mysql_query($query);
$rows = mysql_num_rows($result);
for ($j = 0; $j < $rows; ++$j) {
	$result2[] = mysql_result($result, $j, 'type');
}
$result3 = array_values(array_unique($result2));
function filterTypes($array) {
	$arrayLength = count($array);
	for ($i = 0; $i <= $arrayLength; ++$i) {
		echo "<option value='" . $array[$i] . "'>" . $array[$i] . "</option>";
		}
	}
filterTypes($result3);