Quote:
Originally Posted by Criminal Bizzy
I don't get this last sentence. Do you mean for a set to turn into quads?
No.
Given you have are dealt a pair, the chance of having a
set or quads by the river is 19.2%.
Pr(exactly quads by river given dealt a pair) = C(2,2)*C(48,3)/C(50,5) = 0.082%
Quote:
Originally Posted by statmanhal
No.
Given you have are dealt a pair, the chance of having a set or quads by the river is 19.2%.
Pr(exactly quads by river given dealt a pair) = C(2,2)*C(48,3)/C(50,5) = 0.082%
Typo - answer is 0.82%
Last edited by Mike Haven; 12-26-2019 at 10:24 AM.
Reason: 2 posts merged