Quote:
Originally Posted by statmanhal
You did not understand the first response, which gave you the answer. Let’s review what happened in the hand.
1. You raise to 500, making the pot 700. That 500 is no longer yours – it’s in the pot, up for grabs.
2. Opponent goes all-in making the pot 2000 and you have 1000 to call.
Now it is decision time for you. With a pot of 2000 and 1000 to call, you are getting 2 to 1 pot odds. If you win, you win the pot of 2000. If you lose, you lose the amount you risked when you make the call decision, in this case the 1000 call. The 500 you put in earlier is not part of THIS decision as far a money that you may lose. With 2 to 1 pot odds and 3 to 2 bet odds, it’s an easy call.
For example- if you played this exact hand 5 times,
2 times you win for a total win of 2 * 2000 = 4000
3 times you lose for a total loss of 3 * 1000= 3000
Net profit over 5 hands = 1000, for and average profit of 200 per hand.
EVall-in call = P(win)*Pot – P(lose)*(Bet) = 0.4*2000 – 0.6*1000 = 800 – 600 = 200
I understand this thanks for explaining it in a clear cut way. The thing im stuck at is this problem:
You say 2 times i win for total 4000 and 3 times i lose for 3000 over 5 hands.
But look at it this way:
Over five hands from the start
2 times i win for a total of 3000.
3 times i lose for a total of 4500
So its a loss of 1500 which is a loss of 300 per hand. Obviously calling is the right play in the situation i described and im not trying to say otherwise. Im simply saying how this situation confuses me. Thanks for the help