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Combinatorics of PLO vs NLH Combinatorics of PLO vs NLH

11-17-2014 , 02:51 PM
Hi guys.
If we have this board in holdem:
K 7 2
If I hold 22 and assume that villain is continuing with two pair or better then his possible combos are:
K7 x 9
K2 x 3
72 x 3
KK x 3
77 x 3

can I say that if the same flop was in PLO and I had same 22 withiout K or 7 in my hand the ratio:
(number of hands I beat) / (number of hands I lose to)

is the same since the number of combos of each hand is only multiplied by a constant but the ratio is still the same as in holdem?
Thanks.
Combinatorics of PLO vs NLH Quote
11-17-2014 , 05:25 PM
In terms of the question as you pose it, the answer is yes.
Combinatorics of PLO vs NLH Quote
11-17-2014 , 05:42 PM
Quote:
the number of combos of each hand is only multiplied by a constant but the ratio is still the same as in holdem?
I don't think this is true for realistic, non-100% ranges, which would mean the answer is no in practice.
Combinatorics of PLO vs NLH Quote
11-17-2014 , 06:14 PM
Quote:
Originally Posted by timidcynic
I don't think this is true for realistic, non-100% ranges, which would mean the answer is no in practice.
what do you mean by "non-100% ranges"?
Combinatorics of PLO vs NLH Quote
11-17-2014 , 06:28 PM
Ranges that do not include 100% of starting hands.

Although you are assuming that 72o is in villain's hold'em range so I guess you are assuming 100% ranges.

If you are dealing with realistic ranges, for instance in the 50% region, then the number of combos becomes skewed, because in PLO, there are going to be proportionally more K7 combos than K2 combos, more KK combos than 77 combos, etc., which means the constant changes depending on which hand you're talking about.

This is more or less just my opinion and I could very well be wrong. I am not at all an expert at this. I don't even play PLO. I think you would be better served posting this in the Poker Theory forum though.
Combinatorics of PLO vs NLH Quote
11-17-2014 , 07:19 PM
The ratio of (number of hands you beat) : (number of hands you lose to) would be the same, but the probability that someone has one of the better hands would be higher in PLO for a few reasons.
1. More players typically see flops in Omaha. (Higher VPIP than in NLH)
2. Each villain has 4 cards, not 2, so you're effectively playing against "more hands".
3. If you don't have blockers to KK and 77 in your hand, each villain is more likely to have those sets. Or to put it another way, if your hand was K722, it's almost impossible for a single villain to have you drawing almost dead, since there would only be 2 combos of better sets out there.

These factors combined mean that bottom set is considerably weaker in PLO than in NLH.
Combinatorics of PLO vs NLH Quote

      
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