Show if P(E|F)=P(E) then P(F|E)=P(F)
Join Date: Jul 2009
Posts: 165
No clue how to get this one started...Thanks
Join Date: Jul 2009
Posts: 165
I found it, I will just use the proof of independence..
Join Date: Feb 2010
Posts: 367
Can't be independent one way and dependent the other, unless someone broke the timespace continuum again.
Join Date: Jan 2009
Posts: 5,038
In general, P(E|F) = P(EF/P(F)
Given P(E|F) = P(E), then
P(E)= P(EF)P(F), or
P(EF) = P(E)P(F)
Since P(F|E) = P(EF)/P(E) , we have
P(F|E)= P(E)*P(F)P(E) = P(F)