Quote:
Originally Posted by Dannyz0r
Ok thanks for the help on that one .
The next one i know how to solve but i don't know to write the formula for the random variable
The telephone lines serving an information office are all busy about 60% of the
times. Which is the expected number of tries for succeeding a reservation?
So i'm thinking like this :
0.6+0.6*0.6+0.6*0.6*0.6=0.6+0.36+0.216 >>> 1
so this means in 3 tries i should get a reservation but how does the random variable look like ?
This is a geometric distribution with probability of success 0.4, and the expected value is 2.5.
You need to go back to your course teacher and ask them to go over this stuff with you again. Not trying to be rude but it's clear from the two questions you asked that you have no idea how to solve these, or recognise standard probability distributions.