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Originally Posted by napalm77
how is probability to make flush after discard 4 cards?
Depends on the perspective you choose. From Hero's perspective, since he sees one spade and four other cards, if Villain is drawing four cards to one spade (presuming Villain did not discard any spades), there are 11 missing spades and 31 missing other cards. The number of ways for Villain to catch four spades is
C(11,4)=11*10*9*8/1/2/3/4=330.
The number of ways to draw any four cards is
C(42,4)=42*41*40*39/1/2/3/4=111930.
Thus the probability is 330/111930=0.00295, about one in 339.
From Villain's perspective, since he sees one spade and four other cards, (presuming Villain did not discard any spades), there are 12 missing spades and 35 missing other cards. The number of ways for Villain to catch four spades is
C(12,4)=12*11*10*9/1/2/3/4=495.
The number of ways to draw any four cards is
C(47,4)=47*46*45*44/1/2/3/4=178365.
Thus the probability is 495/178365=0.00278, about one in 360.
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Can I calculate in this way?:
deck 52 cards - 13 cards in same suit, I have one card in suit I+4 cards offsuit, I discard 52-5=47 so (12/47)*(11/46)*(10/45)*(9/44)= 3/1081=0.00277=0.277%
Yes. That's about the same as I got for Villain's perspective. (I rounded differently to show 0.00278 rather than 0.00277).
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deck 32 cards (from 7 do ace) - 8 cards in same suit (7/27)*(6/26)*(5/25)*(4/24)=7/3510=0.0019=0.19%
I don't know what you're doing there.
Buzz