Quote:
Originally Posted by mpethybridge
6. The probability that one of the Vs will flop a set when we flop a set is roughly .095 x .125 - .012, 1.2%
Quote:
Originally Posted by smmcoy
Can you not see that you don't need to multiply by .125 in this equation? The "when we flop a set" already includes that .125. His formula is off by a factor of 8. He already multiplied by .125 in #1. He doesn't need to do it again.
The correct formula is really simple:
1 -41/45 * 40/44 which is 17.2%
So, smmcoy is saying that the odds of set over set on the flop is 4.81:1 when there are only
4 cards available to make that possible.
If I hold KJ, the odds of me flopping 2 pair
[with 6 cards available] is ~48.5:1.
Here's a simple way of doing it:
I have AA & you have KK. The board has to come AKx as we are not concerned with permutations.
So, for the A & K, that's 2[aces]*2[kings]=4 & then multiply that by the
remaining cards in the deck that are not an A or K [2]. 4*44 = 176 possible flops for set over set.
176/19600 possible flops = 0.8979%
Or, you can say: We know I hold AA & you hold KK, so there are only 48 cards available for the flop. So, [48*47*46]/6 = 17,296 possible flops.
176/17296 = 1.01757% & Presto! You've come up with almost [1.5625%] the same answer that you get when you multiply .125*.125.
Think about it. If you flop two pair 2.02% of the time, with 6 possible cards to make it come true, you must flop set over set much less often since there are only 4 cards available to make it come true.
It doesn't matter if the
correct answer is 0.8979% or 1.01757%, or 1.5625%..........Just so long as it's clear to everyone that smmcoy's answer of 17.2% is not even in the same state.
Last edited by ZuneIt; 08-18-2015 at 10:43 AM.