Quote:
Originally Posted by Vanman*
3 A's counts as my oponents would get it in with this holding.
So 12.4% or 17%?
12.4%, final answer
I assume timlagor was just giving an estimate, but for this problem it's not accurate because there are three sources of error, all accumulating with 8 players.
The cards are not replaced so squaring (3/48) instead of decreasing the fraction introduces error. Also, that triple-counts the ways villain can have AAA. To fix the quoted, you can get rid of the squaring and subtract the AAA cases twice so that they're counted just once:
C(4,2)*(3/48)(2/47) - 2*C(4,3)*(3/48)(2/47)(1/46) = 1.55%
Once you have that, you simply multiply by 8 and then you're done since there's no overlap when doing that (only one villain can have AA/AAA since you've removed an ace from the deck). You can't take 1-(.9845)^8 because the players' hands are not independent (that's the third source of error in timlagor's answer).