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Pokercast Episode 39 - Howard Lederer, BryanS & Taylor Caby Pokercast Episode 39 - Howard Lederer, BryanS & Taylor Caby
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09-09-2008 , 12:26 PM
#1
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Live from the Two Plus Two Studios - The feature guest this week on Pokercast is poker pro, WSOP bracelet winner and PPA board member Howard "The Professor" Lederer. Howard comes on the program to share some stories from the legendary Mayfair Club, talk about his involvement with the Poker Players Alliance and discuss the future of online poker. The PokerStars WCOOP Tournament Administrator BryanS is also featured on the program to talk about the now underway World Championship of Online Poker taking place at Poker Stars. Taylor Caby is on the show to announce big news involving Card Runners & Stoxpoker while discussing the future of online poker training. Mike and Adam also talk some tournament news, forum static and of course give away the password for the September 14th Poker Stars VIP Club freeroll.


Pokercast Theme - Demitone Productions Inc. © 2007 : Dodos Blue & Purple - The Dodos © 2008 : TV on the Radio - Wolf Like Me - Return to Cookie Mountain © 2006 : Cut Copy - Light & Music - In Ghost Colours © 2008 : The Clash - The Card Cheat - London Calling © 1979 :
Last edited by Mike Johnson; 09-09-2008 at 01:03 PM.
09-09-2008 , 01:29 PM
#2
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Pictures of the mutant hickey or it didn't happe... er... well this is Bunner after all, nh sir.
09-09-2008 , 02:42 PM
#3
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Loved the Artie Lange/Howard Stern reference. I had just turned off the Stern show when my pokercast finished downloading.
09-09-2008 , 02:44 PM
#4
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wheres the pic of me?
09-09-2008 , 02:45 PM
#5
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Quote:
Originally Posted by GrinningBuddha
Pictures of the mutant hickey or it didn't happe... er... well this is Bunner after all, nh sir.
there is no e in me.
09-09-2008 , 02:47 PM
#6
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Great Show Bunner'sHicky needs its own headset. im tried of sharin with him Lucky he shares the women to.
09-09-2008 , 02:47 PM
#7
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come on i need the pic for the avy.
09-09-2008 , 02:52 PM
#8
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Bunner?

09-09-2008 , 02:54 PM
#9
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Quote:
Originally Posted by tunaman3000
Bunner?
no thats is grandma, would make a great avy for the bunner hicky gimmick though.
09-09-2008 , 02:57 PM
#10
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Quote:
Originally Posted by dangeraw
no thats is grandma, would make a great avy for the bunner hicky gimmick though.
It's actually the Queen of England!
09-09-2008 , 03:20 PM
#11
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Quote:
Originally Posted by tunaman3000
It's actually the Queen of England!
oh so u found me a friend. best gimmick ever amirite.
09-09-2008 , 03:28 PM
#12
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The first problem from Howard was easy:
Spoiler:
Weighting number 1 is 3 balls on one side and 3 balls on the other.
If they are all equal weight the second weighting is simply determined by the two remaining balls.
If one side is heavier than the other the second weighting will be by two random balls of the three from the heavier side.
Two possibilities again: If the weighting is equal, then the third ball not weighted will be the heavy one, or you can easily see which one is heaviest.


On to the next one...
Last edited by *TT*; 09-09-2008 at 03:42 PM. Reason: please add the [spoil] tag around your answers, thanks!
09-09-2008 , 03:34 PM
#13
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Spoiler:
the first one is put four on each side. than take the four on the heavier side and put 2 of them on each side. this will narrow it down to two u than should be to figure it out by holding them in your hand. manholes are round bc the water comes from a toliet bowl which is also round.
i have no idea about the 3rd one.
09-09-2008 , 03:45 PM
#14
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Quote:
Originally Posted by dangeraw
Spoiler:
the first one is put four on each side. than take the four on the heavier side and put 2 of them on each side. this will narrow it down to two u than should be to figure it out by holding them in your hand. manholes are round bc the water comes from a toliet bowl which is also round.
i have no idea about the 3rd one.
Spoiler:

That weighting in your hand is like a third weighting, so your answer is not correct.
09-09-2008 , 03:59 PM
#15
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Quote:
Originally Posted by bellatrix
Spoiler:

That weighting in your hand is like a third weighting, so your answer is not correct.
Spoiler:
no bc he said you can use the weight exactly twice
09-09-2008 , 04:02 PM
#16
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Quote:
Originally Posted by dangeraw
Spoiler:
no bc he said you can use the weight exactly twice
what if the heavier ball is only heavier by 1 gram?
09-09-2008 , 04:02 PM
#17
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Brag: I know the answer to #2

Beat: It's possibly because I work for a construction company.

Spoiler:
It's the only shape that won't fall into itself
09-09-2008 , 04:03 PM
#18
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Quote:
Originally Posted by bellatrix
what if the heavier ball is only heavier by 1 gram?
what if's dont matter.
09-09-2008 , 04:04 PM
#19
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Problem #3

Spoiler:
09-09-2008 , 04:15 PM
#20
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just finished downloading but it's only 23 min?
09-09-2008 , 04:16 PM
#21
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Quote:
Originally Posted by tunaman3000
Brag: I know the answer to #2

Beat: It's possibly because I work for a construction company.

Spoiler:
It's the only shape that won't fall into itself
Spoiler:
arent squares just sa good i think my toliet bowl answer is much funnier
09-09-2008 , 04:40 PM
#22
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Mhmm, the hat problem would make a lot more sense if there were less numbers on the hats than there were # of players. Like if the numbers on the hats would go from 1 to (n-1) then I would have a solution. But from 0 to (n-1), I only get an even distribution.
09-09-2008 , 05:13 PM
#23
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Spoiler:
# 3 you get to talk b4 hand so eveyone just says a different number decide that number b4 you even see the hats.
09-09-2008 , 05:20 PM
#24
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#1

Spoiler:
weigh 3 on each side. If they are the same, weigh the other 2 and you will see the heavier one. If they are different take 2 of the heavier 3. If they are different then you know the heavier one. If they are the same then the odd ball out is the heavier.
09-09-2008 , 05:22 PM
#25
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2nd Question is easy too.

Edit: Plz put in spoiler box!
Last edited by AdamSchwartz; 09-09-2008 at 05:39 PM. Reason: spolier
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