Quote:
Originally Posted by lllGtPhshlll
LoL, you can solve this pretty easily if you assume that the baseball has negligable friction thru flight. This obv isn't a good assumption, but if the frictionless solution is less than 100 yrds, the friction equation will def. be.
V(i) = 82 mph (said u could throw that fast)
theta = 45* (for ball to travel furthest distance w/ negl. friction)
y = 5 ft (initial displacement for height thrown from)
...so change V(i) to ft/s which is 120.27 ft/s .
Now initial y-direction vel. is (120.27)*sin(45) = 85.04 ft/s
X(t) = V(i)*t + (1/2)*a*t^2
Solving for t, you get t = 5.34 s
Now solving for x-direction using t = 5.34 and theta...
X(t) = Vx * t = (120.27sin(45)) ft/s * 5.34 s = 454.13 ft
So basically it is possible when thrown 82 mph and friction is neglected. Unfortunately, that still doesn't say anything about the actual outcome... My guess would be a big fat no thou, and I've watched a decent amount of baseball.
Lol dude WTF are you talking about????. You’ve neglected to take into account the permeating non-sequential factors of {x}*^ 60% mass * velocity
You haven’t even accounted yet for the G-factor of y*z {a*b}+ 50% / (40)* {5*60} = 50^5 - r~ 70
And lol at your assumption that x = {80%*90%/50^}* 2×22 + 1, 72 = 2×52 - 1, 172 = 2×122 + 1
That withstanding the only perceivable outcome that does not conform with the mitigations of {x=7^} is that it seriously detrimentriates against the oblivical intangible force of disconbobulese. Therefore x=r^6%
QED