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Simple algebra sorry

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03-22-2018 , 03:04 AM

bronxsystem

newbie

Join Date: Feb 2018 Posts: 36

Reading Applications of no limit holdem and stuck on page 35. I havent done algebra in ages. Its embarrasing but would appreciate help understand how to arrive at .667

(1-x)(1-0.03)^2 = .667

is this the same as

(1-x)(1-.03)(1-.03)

or is it
(1-x)(.97)^2

feel dumb asking but would really like to understand thank you

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03-22-2018 , 03:50 AM

bronxsystem

newbie

Join Date: Feb 2018 Posts: 36

oops thats the same thing but i still cant get the right answer >< missing something

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03-22-2018 , 03:51 AM

masque de Z

Carpal \'Tunnel

Join Date: Aug 2009 Posts: 9,961

They are all the same thing. a*a=a^2 and if b=1-a then b^2=(1-a)*(1-a)=(1-a)^2. What are you trying to find out?

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03-22-2018 , 03:57 AM

bronxsystem

newbie

Join Date: Feb 2018 Posts: 36

hey
the book gets the answer x = .291
but i just cant get it =/

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03-22-2018 , 04:02 AM

masque de Z

Carpal \'Tunnel

Join Date: Aug 2009 Posts: 9,961

(1-x)(1-0.03)^2 = 0.667 means (1-x)=0.667/(1-0.03)^2=0.667/0.97^2=0.7089 so 1-x=0.7089 hence x=1-0.70289=0.2911

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03-22-2018 , 04:05 AM

bronxsystem

newbie

Join Date: Feb 2018 Posts: 36

i love you. thank you! i see what i did wrong now.
sigh i felt soul crushed not understanding it.
much appreciated.

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03-22-2018 , 04:14 AM

masque de Z

Carpal \'Tunnel

Join Date: Aug 2009 Posts: 9,961

Try also this site for any problem of that type and more difficult eventually, it shows the steps; (0.9409 is 0.97^2)

https://www.symbolab.com/solver/step...7B2%7D%3D0.667

It has various practice tools too to refresh memory and learn new things.

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03-22-2018 , 08:01 AM

bronxsystem

newbie

Join Date: Feb 2018 Posts: 36

awesome site thanks

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03-22-2018 , 10:32 AM

robert_utk

Not From the UK

Join Date: Jan 2005 Posts: 4,822

Yes, awesome link! Thanks!

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