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Serious of -EV into +EV Serious of -EV into +EV

08-12-2018 , 12:24 PM
Quote:
Originally Posted by Lego05
6/18 = 0.3 where the "3" is repeating. Just get a calculator and divide 6 by 18. Then multiply by 100. That gets you the percent chance of 6/18. It is 33.3% where the 3 is repeating.
Yes, sorry, you are correct. I meant 6/16, same number combinations possible.
Serious of -EV into +EV Quote
08-12-2018 , 12:27 PM
Quote:
Originally Posted by robert_utk
PIMP,

One last thought, and then I'm out.

As has been mentioned previously, each of the flips is independent. There is no causal relationship from any previous flip to any current flip. Without causality you can not have a system of related variables.

After every fair flip, the fair penny is still fair.

Now, I choose not to think you are trolling, but you are enjoying all of this somehow. I think there is a mental problem for you that you can not see that what I and others have pointed out is true. I still do not recommend a simulation because you will always get a noisy answer that leaves you hope and fuels your mental problem.

-Rob
OK, I do not know why you are writing here if you do not like me. And most certainly, there is no need to insult me...
Serious of -EV into +EV Quote
08-12-2018 , 12:27 PM
Quote:
Originally Posted by SiberianPIMP
Yes, sorry, you are correct. I meant 6/16, same number combinations possible.
Well, then that is the answer. Something that happens with odds of 6/16 happens with a percent chance of 37.5%. 6/16 = 37.5%
Serious of -EV into +EV Quote
08-12-2018 , 12:55 PM
Quote:
Originally Posted by RustyBrooks
No, but you have to know how many times you're going to repeat each individual "game" in order to make predictions about it.

For example if you repeated the game 1000 times, you'd see 50.5% wins about 15% of the time, just by random chance.

Anyway, I decided to choose a number where getting 50.5% is way outside reasonable chance: I ran it for 1 billion iterations. The result was that you won
50.000415%

I ran it again and you won
49.999897%

Here's the code: https://gist.github.com/rustybrooks/...f7cdbd7921b9a6

It requires a C compiler and CPU that support RDRAND which is a hardware PRNG of high quality.

You run it like
./a.out X Y
where X is the number of times to play and Y is 0 or 1, whether to print the results of each game. (Actually it plays 8*X games, because the random number generator generates 32 bits per call, which is enough for 8 games, and I didn't want to waste any)

So I'd say run it like
./a.out 1 1
which would play your game 16 times and print the result for each one. It prints something like



Try that a few times and you'll see that the logic is right, then try it with something like

./a.out 1000000 0
which will run it a million times and not print each line, just the results. If you print each line it takes a LOT longer to run.
Woow. Thanks man. You are the best. Yeah, that is the proof I was looking for. Nothing like I was thinking/hoping.

Last edited by SiberianPIMP; 08-12-2018 at 01:01 PM.
Serious of -EV into +EV Quote
08-12-2018 , 01:00 PM
Also a question, because I do not understand exactly what script is about. Did you write it in a way that the bold part does not count(for winnings and for losings)? For example:TTHT,HTHT..
Only four, than next four and so on(starting with no.1 coin flip)?
Serious of -EV into +EV Quote
08-12-2018 , 02:06 PM
It does them in batches of 4. It basically takes a series of 4, then breaks them into a 3-sequence, looks up what we would have bet on for that sequence, and then checks if the 4th matches
Serious of -EV into +EV Quote
08-12-2018 , 02:31 PM
Quote:
Originally Posted by RustyBrooks
It does them in batches of 4. It basically takes a series of 4, then breaks them into a 3-sequence, looks up what we would have bet on for that sequence, and then checks if the 4th matches
TNX for this. This is exactly what I wanted. I can not tell you how much thankful I am, that you took your free time and wrote a simulation and helped me a lot. Really appriciate it.
Serious of -EV into +EV Quote
08-12-2018 , 02:34 PM
Quote:
Originally Posted by PairTheBoard
There's a very easy proof if you agree it's a fair coin where P(Heads)=P(Tails)=50%, and that the flips are independent. For every 3-sequence there is exactly a 50% chance the 4th flip makes a winning 4-sequence and a 50% chance the 4th flip makes a losing 4-sequence.


If you deny that then you must either deny that's it's a fair coin or deny that the flips are independent. Which is it?



PairTheBoard
Yeah. I understand it now. To be honest I was thinking they are "some how" connected = if we group them. But yeah, I know... Thanks for taking your time in this thread and for your every post.
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08-12-2018 , 02:37 PM
Quote:
Originally Posted by SiberianPIMP
How do you know this is exact?
Can you prove me this with experiment? I did not see any evidence or proof that this is exact. This is science, so this should be provable with experiment (simulation). I did not see one that I would want to see. The one that I am talking about in first post. As mentioned before, if there is no proof of something: I do not take for granted. I can not just believe, because somebody say something...
Also, not big of a deal if I am wrong, but what if I am correct. I have been reading lately a lot about randomness, there are a lot of smart people that think that we do not understand randomness perfectly. Maybe there is a leak in randomness where I mentioned it...
Yeah, I see now(with proof) that our binomial calculations are not aprox.(very close to real), but are exact.
Serious of -EV into +EV Quote
08-12-2018 , 02:39 PM
@to all
Thank you everybody for every single constructive post in this thread. Appriciate it a lot. I have learned a lot. I hope every reader or poster that was passing by has learned a lot also.
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08-13-2018 , 06:17 AM
I was just looking in slighty wrong direction about how to exploit randomness...

Quote:
Originally Posted by Lego05
Well, then that is the answer. Something that happens with odds of 6/16 happens with a percent chance of 37.5%. 6/16 = 37.5%

I can basically prove this is wrong in the case I mentioned, but instead of 2H2T, TTTT, HHHH, we only take 2H2T(4 flips again). So 6/16 possibilities. We have same betting system(expect it is modified that it does not contain HHHH and TTTT). We start betting at 1st flip.
In this case winning will be more than 37,5%.

Also, I mean offcourse if we calculate in the way everybody is doing right now is just very very close to real(avg) and not exact. And yes we prove this is possible: many -EV into +EV...

And I can prove this without needing any simulation. Just maths....Will post it here soon for debate...
___________
I just needed to write this here. So, I am the first one to prove this(to make equasion for this). Just in case somebody else is close.
Serious of -EV into +EV Quote
08-13-2018 , 07:16 AM
Please no.
Serious of -EV into +EV Quote
08-13-2018 , 08:53 AM
Sorry, no. I modified the program above to exclude TTTT and HHHH, ran it twice with a billion iterations, and it came out
37.499160%
37.499758%
Serious of -EV into +EV Quote
08-13-2018 , 08:54 AM
Quote:
Originally Posted by SiberianPIMP
Also, I mean offcourse if we calculate in the way everybody is doing right now is just very very close to real(avg) and not exact. And yes we prove this is possible: many -EV into +EV...

If you're going to try to "prove" something you need to start out by clearly stating precisely what that something is you want to prove.

Exactly what do you mean by "is just very very close to real(avg) and not exact.".

When you say "many -EV into +EV" do you realize that EV, by definition, is what the average converges to over many trials? So if that EV is negative (-EV) that is already a statement of what happens over many trials. You lose.

If you want to prove something mathematically I strongly suggest you first study mathematics and lots of mathematical proofs.


PairTheBoard
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08-13-2018 , 09:32 AM
Quote:
Originally Posted by NewOldGuy
Please no.
.
Serious of -EV into +EV Quote
08-13-2018 , 10:41 AM
Quote:
Originally Posted by SiberianPIMP
And I can prove this without needing any simulation. Just maths....Will post it here soon for debate...
There really is no debate. The math has already been worked out. The only mathematical thing that has happened so far is that you've misused some formulas because you didn't understand what you were doing.
Serious of -EV into +EV Quote
08-13-2018 , 12:31 PM
Quote:
Originally Posted by RustyBrooks

[redacted text]

But here's what's happened so far
you: here's some math that shows something weird
us: the way you're doing this doesn't work and here's why
you: ok but my situation is actually not covered or explained by this math

If that's how this is going to go, we have a problem: this is a goal post shift.
Quote:
Originally Posted by SiberianPIMP

[redacted text]

Also, what this means?: "this is a goal post shift."
Quote:
Originally Posted by RustyBrooks

[redacted text]

This is what is meant by goal post shifting.

you: if X is true, then my theory is right
me: proves X is false
you: ok, but X is not the right thing, actually if Z if true then my theory is right
me: proves Z is false
you: ok but Z wasn't really the right thing, we have to look at A
and so forth
Quote:
Originally Posted by SiberianPIMP
I was just looking in slighty wrong direction about how to exploit randomness...


[redacted text] instead of 2H2T, TTTT, HHHH, we only take 2H2T(4 flips again).

[redacted text]


__________________________________________________ __________________________________________________ __________________________________________________ ___





Quote:
Originally Posted by Lego05
Well, then that is the answer. Something that happens with odds of 6/16 happens with a percent chance of 37.5%. 6/16 = 37.5%
Quote:
Originally Posted by SiberianPIMP

I can basically prove this is wrong in the case I mentioned, but instead of 2H2T, TTTT, HHHH, we only take 2H2T(4 flips again). So 6/16 possibilities. We have same betting system(expect it is modified that it does not contain HHHH and TTTT). We start betting at 1st flip.
In this case winning will be more than 37,5%.

Also, I mean offcourse if we calculate in the way everybody is doing right now is just very very close to real(avg) and not exact. And yes we prove this is possible: many -EV into +EV...

And I can prove this without needing any simulation. Just maths....Will post it here soon for debate...
I guarantee that you cannot prove that something that happens with a 6/16 chance happens with a chance other than 6/16 because if it happens with a chance other than 6/16, then it does not happen with a chance of 6/16.

Quote:
Originally Posted by SiberianPIMP
I just needed to write this here. So, I am the first one to prove this(to make equasion for this). Just in case somebody else is close.
Nobody else is close.

Last edited by Lego05; 08-13-2018 at 12:40 PM.
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08-13-2018 , 01:24 PM
Quote:
Originally Posted by RustyBrooks
Sorry, no. I modified the program above to exclude TTTT and HHHH, ran it twice with a billion iterations, and it came out
37.499160%
37.499758%
Hi.TNX for this.
I really do not want to post some wrong theory again. That is why I rather ask before.Anybody else is very welcome to help me also with my questions also.

If you run a simulation like descbribed in this post(for a billion trials)? You allways get a number that is lower than 37,5%, right? Or no?

I also do not know if this method that you used will give same results, as for example if script will be written in this way: new 4 flip seq. every time.. 2H2T/all combinations. Maybe different if like this.. Because this is what I am looking for.

Last edited by SiberianPIMP; 08-13-2018 at 01:53 PM.
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08-13-2018 , 01:28 PM
Quote:
Originally Posted by PairTheBoard
If you're going to try to "prove" something you need to start out by clearly stating precisely what that something is you want to prove.

Exactly what do you mean by "is just very very close to real(avg) and not exact.".

When you say "many -EV into +EV" do you realize that EV, by definition, is what the average converges to over many trials? So if that EV is negative (-EV) that is already a statement of what happens over many trials. You lose.

If you want to prove something mathematically I strongly suggest you first study mathematics and lots of mathematical proofs.


PairTheBoard
Hi. TNX for your help.

Yes, I know.
I mean that we are maybe calculating probabilities wrong. The numbers that we get with no. of combinations/all combinations are maybe not exact number.
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08-13-2018 , 01:49 PM
Quote:
Originally Posted by SiberianPIMP
I mean that we are maybe calculating probabilities wrong. The numbers that we get with no. of combinations/all combinations are maybe not exact number.
As a physical matter, it's possible that coins are not perfectly balanced for flipping. Depending on the methodology used, it's possible to bias results slightly depending on the way that the coin is manufactured. For example:

* The edges of coins are very slightly beveled so that they release from the mold properly, which slightly biases them if they spin on a table before settling.
* The weight of each face of the coin may vary slightly, causing bias as the coin bounces/spins before settling.
* There may be physical defects for any specific coin that is being flipped that may cause bias.

But none of these physical features will be captured in a simulation. There have been various studies of this bias that you can look up for yourself. These are all dependent upon the specific coin itself.

However, the larger point is that the math is still precise in the sense that once the bias is known (say, 50.5% heads/49.5% tails), the math can be worked out. And the bottom line is that if you have a coin that's biased towards heads, then if the payout is even money you gain an EV advantage by just betting heads ALL THE TIME. All the fancy waiting to see X tosses before making a wager has ZERO impact on the outcome as long as you believe that the coin flips are truly independent of each other (by definition of what independent events are).

All of this is understood under the existing framework of probability. As much as you may want to believe you have some super-clever insight that completely destroys everything we know about probability, the reality is that it's highly unlikely (especially given the depth of knowledge we have in this area) and that it's far more likely that whatever "system" you think you come up with is either wrong or easily explained in the existing knowledge framework.

Edit:

Quote:
37.499160%
37.499758%
Quote:
If you run a simulation like descbribed in this post(for a billion trials)? You allways get a number that is lower than 37,5%, right? Or no?
No. The fact that you think two consecutive results that are just below 37.5% (on the order of 0.001%) is a pattern that can be extrapolated is a strong sign that your basic understanding of probability is flawed. There was about a 25% chance of that happening.
Serious of -EV into +EV Quote
08-13-2018 , 01:53 PM
Quote:
Originally Posted by SiberianPIMP
I mean that we are maybe calculating probabilities wrong. The numbers that we get with no. of combinations/all combinations are maybe not exact number.
It might be worth your time watching this playlist:

https://www.youtube.com/playlist?lis...ar3GQVfZD4SlbX

and lecture 1 of this playlist:

https://www.youtube.com/playlist?lis...Q6ht66KWxbzTIo

and lecture 4 of this playlist:

https://ocw.mit.edu/courses/electric...ideo-lectures/

Juk
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08-13-2018 , 01:56 PM
Quote:
If you run a simulation like descbribed in this post(for a billion trials)? You allways get a number that is lower than 37,5%, right? Or no?
No

Quote:
I also do not know if this method that you used will give same results, as for example if script will be written in this way: new 4 flip seq. every time.. 2H2T/all combinations. Maybe different if like this.. Because this is what I am looking for.
It uses a new 4 flip sequence every time. We've been over this more than once.
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08-13-2018 , 01:59 PM
@jukofyork, RustyBrooks, Aaron W.

TNX all of you.
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08-13-2018 , 06:00 PM
Quote:
Originally Posted by Aaron W.
As a physical matter, it's possible that coins are not perfectly balanced for flipping. Depending on the methodology used, it's possible to bias results slightly depending on the way that the coin is manufactured. For example:

* The edges of coins are very slightly beveled so that they release from the mold properly, which slightly biases them if they spin on a table before settling.
* The weight of each face of the coin may vary slightly, causing bias as the coin bounces/spins before settling.
* There may be physical defects for any specific coin that is being flipped that may cause bias.

But none of these physical features will be captured in a simulation. There have been various studies of this bias that you can look up for yourself. These are all dependent upon the specific coin itself.

However, the larger point is that the math is still precise in the sense that once the bias is known (say, 50.5% heads/49.5% tails), the math can be worked out. And the bottom line is that if you have a coin that's biased towards heads, then if the payout is even money you gain an EV advantage by just betting heads ALL THE TIME. All the fancy waiting to see X tosses before making a wager has ZERO impact on the outcome as long as you believe that the coin flips are truly independent of each other (by definition of what independent events are).

All of this is understood under the existing framework of probability. As much as you may want to believe you have some super-clever insight that completely destroys everything we know about probability, the reality is that it's highly unlikely (especially given the depth of knowledge we have in this area) and that it's far more likely that whatever "system" you think you come up with is either wrong or easily explained in the existing knowledge framework.
Excellent summary
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08-14-2018 , 07:45 AM
Quote:
Originally Posted by RustyBrooks
Sorry, no. I modified the program above to exclude TTTT and HHHH, ran it twice with a billion iterations, and it came out
37.499160%
37.499758%
I really do not want to troll(because you were really helpful), but if you did it like this:
"It does them in batches of 4. It basically takes a series of 4, then breaks them into a 3-sequence, looks up what we would have bet on for that sequence, and then checks if the 4th matches."
and than give out HHHH and TTTT.. This is not correct way. In previous system was possible to bet on only last flip because it has exactly 8/16 combinations.

I modified betting system for only 2H2T:

(I made it for 0EV game, so I think it is easier to understand). Here is example how it works:

We allways start with betting (we allways start with 6 units;we look at the line: on every flip) 3 units on T and we also bet 3 units on H, if T(1. Flip; we have 6 units) falls, we than bet 2 units on T and we also bet 4 units on H. If H (2. Flip; we have 8 units) falls, we than bet 4 units on T and we also bet 4 units on H. If H(3. Flip;we have 8 units) falls, we than bet 8 on T. If T falls(4. flip) we have won 16 units. Offcourse, we can miss a bet at a flip when a line tells us that we need to bet same amount of units on H or T, but because this is example how betting works I did not make any simplicity.
_______________
And as mentioned before, I do not think simulation will be needed. Will post here a bit later...
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