Quote:
Originally Posted by BryanC
So basically It would be cool if somebody could help me to match up these different types of hands to the correct equations. I'm just a little bit confused with regards the definitions of mutually exclusive events, independent events and dependent events as they relate to different types of poker hands on the flop.
There is no magic formula that says you have to apply this equation or that other one to a particular situation. But there's a few things that are always true, and you can use that for a few tricks.
Let's take an example: you have 3
3
in the big blind. It is folded to the small blind, who limps. For the sake of the example, you check. What is the chance of you hitting another 3 on the flop? You could pretend that the flop cards are turned over one by one, and ask: what is the probability of the first flop card being a 3? Well, you know your 2 hole cards, 50 cards are unknown. 2 of them are 3s, so the probability is 2 in 50, or 4%. A quick'n'dirty argument would extend that to 3 cards and say: the chance of hitting a set is roughly 12%.
You would be making a mistake there, though not a big one: the two 3s hitting the 3 flop cards are not
statistically independent events. For example, the 3
being the first flop card, and the 3
being the second flop card are
mutually exclusive, they cannot happen on the same flop (and if they do, someone's got some explaining to do).
Furthermore, the chance of any 3 hitting on the second flop card depends on whether the first flop card was a 3 or not. If the first card missed, there's 2 of 49 unknown cards that improve your hand, but if it hit, there's only one 3 left in the deck. So the probability of hitting on card 2 depends on card 1, these cards are
statistically dependent.
To find out what the chance of any 3 hitting on the flop is, you could write down all possible ways the three cards can come with at least one 3. Ignoring suits, there's 6 of them: miss-miss-hit, miss-hit-miss, hit-miss-miss, miss-hit-hit, hit-miss-hit, and hit-hit-miss. To calculate the overall chance of hitting at least one 3, you could calculate the probability of each outcome, and then add them up. This would be correct, but cumbersome. Cumbersome, but not wrong.
Fortunately, there is a shortcut. Just as correct, but easier: you either hit at least one 3, or you don't. So the probability of hitting at least once plus the probability of missing on all three flop cards must be 100%. So p(yippie)=1-p(duh). Turns out p(duh) is vastly easier to calculate, because there is only one outcome: miss-miss-miss. So:
p(duh)=48/50 * 47/49 * 46/48 = 0.8824
p(yippie) = 1 - p(duh) = 11.75%, or 7.5-to-1.
See, there's no right way and no wrong way. But there is an easy way and a complicated way.
Last edited by wallenborn; 01-15-2008 at 08:11 PM.
Reason: Not good at math