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Old 11-02-2018, 02:24 PM   #601
HighOctane
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Re: No-Limit Hold ’em For Advanced Players by Matthew Janda Reviews and discussion

^^ Nevermind I think I found my answer as I went through this whole thread.
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Old 11-02-2018, 05:37 PM   #602
Matthew Janda
 
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Re: No-Limit Hold ’em For Advanced Players by Matthew Janda Reviews and discussion

Quote:
Originally Posted by HighOctane View Post
^^ Nevermind I think I found my answer as I went through this whole thread.
you the real mvp
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Old 11-02-2018, 10:12 PM   #603
Tiltedmisery
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Re: No-Limit Hold ’em For Advanced Players by Matthew Janda Reviews and discussion

I confused about some math. I have the first addition third print. In part two chapter "Examining Complex Ranges- Defending Enough Against Opens," page 61, there is this equation to get the frequency of how often btn will get 3bet, and to solve it you have to know how often the blinds would 3bet. say SB 3bet 16% and BB 14%.

And this is whats in the book:

0.278 = 0.16 + (0.84)(0.14)

On the page before is the same situation, finding frequency of btn facing a 3bet. where each blinds 3bet 12.5% each.

0.234 = 1 - (0.875)^2

so it looks like:

1 - (freq of SB not 3betting)(freq of BB not 3 betting)

So why is it so different on the next page? why is it 0.16 + (0.84)(0.14)?

shouldnt it be:

2.776 = 1 - [(1 - 0.16)(1 - 0.14]) ???

Can someone also explain how this equation? 0.16 + (0.84)(0.14)?

i think there is also a typo on the same page which got the math wrong. This equation deals with finding freq of blinds calling where SB calls 8% and BB calls 20%.

0.217 =(0.08)(0.86) + (0.2)(0.74)
where:
0.86 = fraction of time BB does not 3bet
0.74 = fraction of time SB fold to BTN open

But SB 3bet 16% & calls 8% for a total of 0.24, so Sb actually fold 0.76 of the time.

Last edited by Tiltedmisery; 11-02-2018 at 10:37 PM.
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Old 11-09-2018, 12:44 AM   #604
statmanhal
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Re: No-Limit Hold ’em For Advanced Players by Matthew Janda Reviews and discussion

Quote:
Originally Posted by Tiltedmisery View Post

2.776 = 1 - [(1 - 0.16)(1 - 0.14]) ???

Can someone also explain how this equation? 0.16 + (0.84)(0.14)?
The two equations equal to the same result.

Given events A and B, the probability at least one happens is

P(A or B) = 1- P(not A)*P(not B) = P(A)+ P(not A)* P(B),

assuming the events are independent.
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