Quote:
Originally Posted by 1p0kerboy
I need some help if one of you math gurus has a spare second.
On page 112, which is the introduction to half-street games, towards the Is P the pot size or the probability?
How can P(1 -c), which is the frequency that X folds be the same as c, which is the frequency that X calls, unless it's 50%?
page 112
P=pot size, not probability
c=frequency (proportion) of time X calls
1-c= frequency (proportion) of time X folds
bluff bet= size of pure bluff bet =1 unit always
MOP is trying to determine how often X needs to call to breakeven with Y versus a pure bluff bet by Y when pot size=P. Say the pot is 5 dollars. Y bets 1 dollar with total trash so that when X calls, Y loses 1 dollar all of the time. If X folds, Y wins 5 dollars. Then MOP says X should call c=p/(p+1)=5/(5+1)=5/6. If X calls 5/6 of the time do the payers breakeven?
verifying from Y's view EV=($5)1/6+(-$1)5/6=5/6-5/6=0. Yes
in general then for EV=0, you would want ($P)(1-c)+(-$1)(c)=0 then dropping the dollar signs and applying algebra in baby steps:
P(1-c)=c
P-Pc=c
P=c+PC
P=c(1+P)
c=P/(1+P)
hope this helps