Im a newbie to poker and most of my friends played very occasionally. We we playing texas hold'em with 7 people. 4 people folded. The round ended with 3 of us going all in.
When we flipped the cards we were all astonished to find all 3 of us has the same hand (different suits of course).
My question is [B]what are the odds of that? It has to be in the millions right. 7 people in the game. 3 are delt the same hand. We were playing with a single deck.
Obviously we went NUTS when we saw the results. Ive been looking for an online calculator to find out what the odds/probably are. But I can't find one. Is there anyone on here thats a mathematical genius?
Im simplifying the round but in case you were wondering:
Player 1: Fold
Player 2: Fold
Player 4: Fold
Palyer 5 : J, Q
Player 6: J, Q
Player 7: J, Q
Community Cards: 4,3,9,8,10 (yup a 10 on the river!!!)
well let's see. the first player doesn't matter what they have, as long as it's not a pair, so call it happening 94% of the time.
first card for player two is any six from 50, so 12%
second card for player two is any three from 49, so 6%
first card for player three is any four from 48, so 8%
second card for player three is any two from 47, so 4%
multiply them all together, and that gives an 0.00022 chance. so not even close to millions.
edit - this is just back of a cig packet calculations, and is just considering three specific players, not any three from seven. but it's not going to be anywhere near as unlikely as you think.
