Quote:
Originally Posted by YoungStro
Hey I was just looking into the same thing and came across this thread. How do we calculate this in PLO, where they can literally have any combination of hearts? I was always really bad with this stuff in math class. Is it just 11^2? Combination? Permutation?
Assuming someone is playing a very wide range, but they have two cards of the same suit, there are only 78 possible combos of suited hands in a particular suit, prior to the flop. (i.e. one of 32s in hearts, one of 42s, one of 52s etc).
You get to 78 because there are 12 combos of Axs (in a specific suit), 11 of Kxs, 10 of Qxs... down to 1 of 32s.
12+11+10+9+8+7+6+5+4+3+2+1 = 78.
If that player then sees a flop with 2 hearts in his hand and 2 hearts on the board, he has 55 combos of flush draws.
Bear in mind that even if you only play double-suited hands in PLO, when the flop contains a flush draw, over 50% of your hands do not have that draw, since they will be in the "wrong" suits. Also remember that in PLO, weak flush draws are
usually quite bad hands that can get you into a lot of trouble. Even with 4 holecards, it's pretty hard to flop a draw to the nuts.