Quote:
Originally Posted by minamo99
I actually have a follow up math question on this, if anyone would be willing to help me on this that would be great. Suppose I'm holding any 2 suited cards. There's 3 cards of the same suit on the flop. What's the chance that another one come on the river or turn? And what are those odds when Villain has at least 1 of similar suit?
If my math is right:
52 cards in the deck, two in your hand leaves 50.
3 of that same suit come on the flop, leaving 47 possible cards to come.
Each suit has 13 cards; you have 2 and there are 3 on the board, leaving 8 of that suit in the deck or in the villains hand.
So the probability of a card of the flopped suit being in the villains hand is 8/47 or 14%. The approx chance of another of that same suit dropping on the turn OR the river is 8/47+8/46 or 34.5%.
Now the probability of the villain holding one of the same flopped suit AND that same suit turning or rivering is: (8/47 (villain hole card)) * 7/47+7/46 to account for one being in his or her hole cards. That comes to 15% chance that all three conditions are met.
I need someone to verify the math though.