I have a question regarding "Professional No Limit Hold'Em: Vol 1" specifically Hand No. 2 and 3 in the chapter called "Fundamentals in Practice" on page 87.
Hand No. 2. You have $100 on the button in a $1-$2 game. An
aggressive player who has $800 opens for $6, another player calls,
and you call with 6
6
. The blinds fold, and the flop comes
7
5
4
, giving you a pair and an open-ended straight draw. The
pot is $21.
Your aggressive opponent bets $20, and the next player folds.
You have $94 remaining. This flop is excellent for your hand,
giving you a nearly 1 in 3 chance of making a straight by the river.
(By the Four Times Rule it's 32 percent.) Plus, you could draw
out on a bigger pair by catching a set, and you may even have the
hest hand.
Quote:
You have a strong enough hand to commit on the flop.
The hest play is to raise all-in, which is $74 more into a $61 pot.
If your opponent doesn't have a decent hand, he'll be forced to fold.
If he calls, you have an excellent chance to draw out.
Its the quote above... I don't understand how the authors calculate the pot to be 61$,
when the pot on the flop was 21$ + the 20$ bet from our aggro opponent?
Any answer will be greatly appreciated