Math Gap in Knowledge - Beginning Poker Questions

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Math Gap in Knowledge

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04-11-2018 , 07:22 AM

Feldheimer1

journeyman

Join Date: Dec 2017 Posts: 244

Hi all,

Got a maths question I am not certain about.

When dealing with ranges, let's say a player has a 60/40 value/bluff range. If we say that the player's value range consists of AK and JJ+, so 16c + 6+6+6+6c, totalling 40 value hands, how many combinations of bluff hands must they have to be balanced?

I'm not quite sure how to work this one out.

Thanks in advance and have a good one!

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04-11-2018 , 07:44 AM

Smeags

enthusiast

Join Date: Mar 2018 Posts: 52

Here's the mathematical answer...

(40 (the number of hands) x 100 ) / 60 (the percentage) = 66.6.
66.6 - 40 = 26.6.

So you should have 26.6 bluff hands.

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04-11-2018 , 07:51 AM

AliceWhat

enthusiast

Join Date: Feb 2018 Posts: 85

Quote:

Originally Posted by Smeags

Here's the mathematical answer...

(40 (the number of hands) x 100 ) / 60 (the percentage) = 66.6.
66.6 - 40 = 26.6.

So you should have 26.6 bluff hands.

Where did 66.6-40 come from?
It's 40×2/3, and that's 26.6* indeed, but I just don't get where 66.6-40 is coming from.

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04-11-2018 , 08:00 AM

Feldheimer1

journeyman

Join Date: Dec 2017 Posts: 244

Got it, so [value hands*100 divided by % of value hands]. Thanks!

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04-11-2018 , 08:02 AM

ArtyMcFly

Carpal \'Tunnel

Join Date: Dec 2014 Posts: 13,252

If it's 60/40 in favour of value and and there are 40 value combos, the bluffs combos will be 40/60 * 40 = 26.67

To use the same math on different numbers... If it's 55/45 and 100 value combos, the bluffs will be 45/55 * 100 = 81.8. (100:82 is roughly the same ratio as 55:45 or 11:9).

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