A page of statistics about Colossus at
http://www.wsop.com/promotions/files...he-numbers.pdf

includes the stats:

Total # of Entries: 22,374
Total Prize Pool: $11,187,000
Total Places Paid: 2,241
1 st Place Prize: $638,880 (1,130 times the buy-in)
2241st Place: $1,096
Total # of Unique Entries: 14,284 (64% of entries) (New WSOP record)
(Bests 2006 WSOP Main Event - 8,773 – by a whopping 63%)
Total # of Players Re-Entering: 6,641 (46.5% of uniques)
# of Players Re-Entering Once: 4,885 (thus 1,756 players re-entered
more than once)

Adding up 14284 people entering the first time, plus 6641 players
entering a second time, plus 1756 people entering a third time gives a
total of 22681, not even including the entries from those who entered
a fourth time.

22681 - 22374 (stated) = 307 buyins missing.

Not sure if the above numbers include any refunds. But would that explain all the missing buyins?

The only thing I can come up with is that the 6641 number includes unique people that entered 2, 3 or 4 times, not number of entries.

So 14284+4885=19169 is the number of entries excluding 3rd and 4th entries, which I believe we can not determine from the data provided.

i entered a guess in the nvg guess the entrants competition. i demand to be compensated now that these details have come to light

How many chips in play?

111,870,000 according to wsop chip counts.

According to the updates, there were between 112 and 113 million chips in play.

There were many individuals who pre-registered for multiple and/or all start "days" (1A, B, C, D).

If they succeeded in getting to day 2 and still had starting days paid for, they were refunded.

All of the refunds should have been removed from the numbers in that pdf.

So Nimbus' calculations are correct and something is off with those tallies. Difficult to know where the mistake is without the real data.

I spent some more time on this, and I believe we can calculate the number of players entering three and four times, but I am coming to a similar conclusion that the reported numbers don't add up. I'm sure it can be explained by the number of refunds due to unregistering or making day 2, but it would be nice if the reported numbers reflected that.

A = Number of people that entered exactly once
B = Number of people that entered exactly twice
C = Number of people that entered exactly three times
D = Number of people that entered exactly four times

1. From the unique entries number, the following should be true:

A + B + C + D = 14,284

2. Total entries:

A + 2B + 3C + 4D = 22,374

3. To find A, we should subtract re-entries from unique entries:

14,284 - 6,641 = 7,643

4. B is specifically stated as 4,885.

5. 1,756 players entered more than once:

C + D = 1,756
or:
C = 1,756 - D

6. First formula:

7,643 + 4,885 + 1,756 = 14,284 (no problem)

7. Second formula:

7,643 + 2(4,885) + 3C + 4D = 22,374
3C + 4D = 4,961

8. Use #5 with #7:

3(1,756 - D) + 4D = 4,961
5,268 - 3D + 4D = 4,961
5,268 + D = 4,961
D = -307 (it's problem)

Please let me know if you think I made a mistake somewhere.

The computer system treated each wave as a separate event.

It was possible to register as many as 12 times since there were three waves of each flight.

KLO3, I interpret the WSOP sheet as

A= 14,284 entered once only
B= 4,885 entered twice

more than twice (could be many if they started a few waves)
6642 - 4885 = 1757


chip in play counts are deceptive because each time they get rid of a small chip denomination, they have run-offs and add chips to tournament as they round up on every table.

Why do you guys make math more difficult than it needs to be?

112,850,000= total chips at final table (A)

5,000= starting stack (B)

A/B= 22,570 entries

A difference of 196 from reported numbers (22374)

I dont think we can say 196 stacks were blinded off and put into play (98,000 extra chips). I understand color up, but there are race offs and minimal chips chips are actually added into play. Maaaaaybe but its a stretch.

Chimp, we'll be easy on you since you're only a primate, but you're missing the point. The chips don't factor into the discrepancy we're talking about, although they can be added to the discussion of any possible theories. But the point is that the entry numbers themselves don't make sense.

There are 4 numbers that don't add up:
22374 total entries
14284 unique entries
6641 players that re-entered one or more times
4885 players that re-entered only once

Going off of # of entries by each individual it works out to:
First bullet: 14284
Second bullet: 6641
Third bullet: 1756
Fourth bullet: ?

We don't know the 4 bullet number, but the problem is that count of people that fired 1, 2, or 3 bullets already adds up to more than 22374. So it doesn't matter; something is wrong with those entry numbers. We hope it's not the 22374 number but that could be one of the mistakes here.

Doublejoker saying that people could've entered more that 4 times just makes it worse (if that actually happened).

i think you guys are wasting too much on this. I know someone who initially did not have his refund approved for some reason (even though he did not show up for the flight). Today he could pick up his money. There may have been some errors in the refund process or the floor not accounting for people who don't show up properly??? Hard to say. Most likely has something to do with this.

The best case is that it was sloppy accounting. The worse case is someone stole the money.

300 buyins x $500 = ~$150,000 missing

So the casinos never run numbers like this for a tournament which serves as a double-check on the chip count and/or money payout integrity?

Why don't they do it? I've always wondered that because I've always known they could run these double-checks and they never do. Are they afraid of revealing too many "Christian Lusardi" type of grifters at work? Too many "Men" teams at work? LOL @ tournament poker.

Hell, these days, with RFID chips, they should be able to give EXACT chip counts for any player at any time, and to make sure they know when extra chips have entered (or left) play.

Maybe some day we'll have 10 networked RFID readers at every table, but for now that would probably be too much of an expense for the WSOP, considering both hardware and software development cost. Would be cool, though. And it wouldn't have the same concerns as RFID cards, since it wouldn't matter if someone else could "read" your chip stack.