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07-15-2021 , 08:30 PM
I recall when I was a kid, these were called "Einstein Puzzles" (lol) and published in magazines. It'd usually be something like the names, colour of a house, pet owned, kids name, or something. Usually about 4 variables. I learnt to solve them when I was about 11.
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07-15-2021 , 08:34 PM
Also, I can do cryptogrpahs by sight. Find the E's and the S's, and you're gold. I used to play Scrabble with people who are now national champions.
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07-15-2021 , 08:38 PM
Quote:
Originally Posted by ecriture d'adulte
Correct. And I fail for not reading the whole thing as the article explains exactly what they use it for



See 2 more questions will follow ups for each. here.

Joel David Hamkins is also famous for being the highest rated rated poster on MathOverflow. No small feat given multiple Fields Medalists and all sorts of top notch mathematicians are active there.
https://math.stackexchange.com/users/244722/brucez

Also a previously active poster...
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07-15-2021 , 09:44 PM
Math stack exchange is not the same as math overflow. Undergrad or below level stuff is fine on stack exchange. Math overflow is basically research level. Though they let later grad school stuff in.
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07-15-2021 , 10:00 PM
Quote:
Originally Posted by d2_e4
https://math.stackexchange.com/users/244722/brucez

Also a previously active poster...
just some maths homewwork guy I hear

You may also recall giving me grief for using a similar method when interviewing programmers
Quote:
All the puzzles come from the drawer of mathematical philosopher Joel David Hamkins’ Oxford interview questions. Hamkins is Professor of Logic and the Sir Peter Strawson Fellow in Philosophy at University College, Oxford. He says that the college likes to get student candidates to work though some logical reasoning since this gives them insight into how they approach thinking about a new topic. “We also get to see a little of their personality, their tenaciousness, and their ability to discuss something rationally without yet knowing all about it, including their ability to accept helpful suggestions from others. So the interview isn’t just testing whether they can solve the puzzle on their own in isolation, but we get to see the whole process of their solution attempt unfold as it happens, and that is what is valuable for admissions evaluation.”
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07-16-2021 , 04:05 AM
Quote:
Originally Posted by d2_e4
Also, I can do cryptogrpahs by sight. Find the E's and the S's, and you're gold. I used to play Scrabble with people who are now national champions.
Was a bit drunk last night, sorry, meant codewords. These things:



That was the first one that came up on google images. They gave you the "S", too easy! Not too many 10-letter words have "SF" in them. MISFIRING would be one, but that doesn't work as the I's repeat and the letters in that word don't repeat. So it has to be DISFAVORED. If that's right, it's basically solved, the rest is just filling in the blanks.

****, I just saw the T is given as well... so it's DISFEATURE.

Wait, that doesn't work either. Is this a trick puzzle???

Haha. MISFORTUNE. Ok, I cheated and used a crossword solver for that. I'm rusty.

Last edited by d2_e4; 07-16-2021 at 04:15 AM.
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07-16-2021 , 10:13 AM
Quote:
Originally Posted by Willd
Spoiler:
A2
Logic in spoilers

Spoiler:

Mary not knowing obviously rules out row 3
Mary knowing that Jane doesn't know tells us that there for every column that has a blue square in the correct row there must be at least one other blue square in that column. This rules out row 4, as if it was in C4 then Jane would know so Mary couldn't say with certainty that Jane doesn't know.
Having ruled out rows 3 and 4, the only way that Jane can now know where the prize is is if there is exactly one blue square in rows 1 and 2 of the correct column. This is only the case for column A, so the prize must be in A2.
Help me with one proof in your logic set. (bolded)


Spoiler:

Mary not knowing obviously rules out row 3
Mary knowing that Jane doesn't know tells us that there for every column that has a blue square in the correct row there must be at least one other blue square in that column. This rules out row 4, as if it was in C4 then Jane would know so Mary couldn't say with certainty that Jane doesn't know.
Having ruled out rows 3 and 4, the only way that Jane can now know where the prize is is if there is exactly one blue square in rows 1 and 2 of the correct column. This is only the case for column A, so the prize must be in A2.


Spoiler:

I see Row 3 and Column C easily ruled out.

But in Row 4 what is it that allows them to exclude either 4A or 4D as BOTH being LIVE potential hosts and thus keeping that Row in play?
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07-16-2021 , 10:25 AM
Quote:
Originally Posted by Cuepee
Help me with one proof in your logic set. (bolded)


Spoiler:

Mary not knowing obviously rules out row 3
Mary knowing that Jane doesn't know tells us that there for every column that has a blue square in the correct row there must be at least one other blue square in that column. This rules out row 4, as if it was in C4 then Jane would know so Mary couldn't say with certainty that Jane doesn't know.
Having ruled out rows 3 and 4, the only way that Jane can now know where the prize is is if there is exactly one blue square in rows 1 and 2 of the correct column. This is only the case for column A, so the prize must be in A2.


Spoiler:

I see Row 3 and Column C easily ruled out.

But in Row 4 what is it that allows them to exclude either 4A or 4D as BOTH being LIVE potential hosts and thus keeping that Row in play?
Spoiler:
Consider what happens if Mary was told Row 4. She would know that one of 4A, 4C or 4D was correct. However since 4C is a possibility then as far as Mary knows Jane could have been told column C, in which case Jane would know, so this means that if Mary was told row 4 then she would not be able to make the statement about Jane not knowing.
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07-16-2021 , 05:04 PM
Quote:
Originally Posted by Willd
Spoiler:
Consider what happens if Mary was told Row 4. She would know that one of 4A, 4C or 4D was correct. However since 4C is a possibility then as far as Mary knows Jane could have been told column C, in which case Jane would know, so this means that if Mary was told row 4 then she would not be able to make the statement about Jane not knowing.
One last attempt as i am clearly missing something.


Spoiler:

Given what Mary says:

- Yes Jane clearly can say it is not at C4 based on what Mary would instantly know if it was...
- But in Janes view neither A4 nor D4 can be excluded (??) by Mary as potential hosts ...or can they? If so, how?


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07-16-2021 , 08:04 PM
Quote:
Originally Posted by Cuepee
One last attempt as i am clearly missing something.


Spoiler:

Given what Mary says:

- Yes Jane clearly can say it is not at C4 based on what Mary would instantly know if it was...
- But in Janes view neither A4 nor D4 can be excluded (??) by Mary as potential hosts ...or can they? If so, how?


Spoiler:
I'm not sure if I'll be able to make it much clearer but I'll give it another go.

Assume Mary was told the prize was in row 4. Mary doesn't know exactly where the prize is but knows it must be in A4, C4 or D4. If the prize was in A4 or D4 then Jane also wouldn't know where the prize is, however if the prize was in C4 then Jane would know the prize is. This means that Mary does not know whether or not Jane knows where the prize is and therefore would not be able to make the statement that Jane also does not know where the prize is. Since Mary did make that statement (and we are told the statements are correct) then this contradicts our initial assumption so Mary must not have been told row 4.

By using this logic (and the more straightforward fact that it can't be row 3 or Mary would have known the location) Jane can rule out Mary having been told that the prize is in row 3 or 4. Having done this it's hopefully obvious that Jane must have been told column A because otherwise she would still not know where the prize is (it could be either row 3 or 4 if she had been told column B or D).


An interesting addendum to the puzzle that occurred to me while writing this. Consider exactly the same board but this time Mary was told the column and Jane the row. Both Mary and Jane make the same statements and neither makes a mistake, i.e.:

Mary: I don't know where the prize is and I also know that Jane does not know where the prize is.
Jane: I now know where the prize is.

Where is the prize now?

Spoiler:
This is essentially the same puzzle but it was interesting to me that it still works with the knowledge reversed but results in a different answer.
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07-16-2021 , 08:58 PM
Quote:
Originally Posted by Willd
An interesting addendum to the puzzle that occurred to me while writing this. Consider exactly the same board but this time Mary was told the column and Jane the row. Both Mary and Jane make the same statements and neither makes a mistake, i.e.:

Mary: I don't know where the prize is and I also know that Jane does not know where the prize is.
Jane: I now know where the prize is.

Where is the prize now?

Spoiler:
This is essentially the same puzzle but it was interesting to me that it still works with the knowledge reversed but results in a different answer.
Spoiler:
Funny enough I initially had meant to say numbered row and lettered column in the OP so it was obvious even if you didn't know the convention. But I liked the fact that it still happened to work so I left the mistake since someone using the opposite convention could still correctly explain their answer.
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07-24-2021 , 03:35 PM
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07-24-2021 , 04:47 PM
"Intellectually active" is a big compliment in that community. I'm taken back a few years to when Michael Atiyah "proved" the Riemann hypothesis. Don't think "intellectually active" is going to be in his obit.
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07-25-2021 , 02:07 AM
I remember reading The First 3 minutes as a kid.

A great life
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07-25-2021 , 01:50 PM
In Atiyah's defense he was pretty self aware about being an old man who had sort of lost it. Weinberg seemed to avoid the trap that people like Atiyah or Einstein fell in by switching over to astrophysics later in his career. Smart move because there haven't been a ton of new predictions that one could make in high energy physics while he was able to predict/guess the nonzero value of the cosmological constant a few years before it was measured via anthropic constraints, though not without some controversy. His main argument was we shouldn't expect the CC to be too much smaller than the highest it could be and still allow for galaxy formation. And that's kinda sorta what the observational astronomers later found. I think Witten and most of the high energy crowd were hoping for 0 so one could hold out for a clean explanation as to why. AFAIK Weinberg was unique in anticipating the messy situation we ended up in.
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10-04-2021 , 12:02 AM
Interesting b log post by Peter Scholze on the state of interactive proof assistants.It's getting easier and raiser to envision a future where math is too hard for mathematicians....or at least human ones.
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10-17-2021 , 01:26 PM
Has anybody ever proved that, regarding the twin prime problem, there cannot be an algebraic type algorithm that when applied to a group of squished numbers yields a result that is either a higher squished number or a result that points to the existence of some higher squished number?
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10-17-2021 , 02:58 PM
I would guess no. Just because I don't think anybody could make sense of what you're trying to say from that.
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10-18-2021 , 01:43 AM
Quote:
Originally Posted by ecriture d'adulte
I would guess no. Just because I don't think anybody could make sense of what you're trying to say from that.
Take all the primes. Squish them together. Add 1. The result is either prime or squish.
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10-18-2021 , 01:47 AM
I think if we squish together the zeros of the Riemann zeta function, we could get lots and lots of primes in a row.
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10-18-2021 , 09:10 AM
When you squish two zeros together you get eight.
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10-18-2021 , 09:19 AM
Quote:
Originally Posted by Trolly McTrollson
When you squish two zeros together you get eight.
I thought that was infinity.
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10-18-2021 , 09:52 AM
Quote:
Originally Posted by Trolly McTrollson
When you squish two zeros together you get eight.
Joking aside, if you can find a zero of the analytical continuation of the zeta function with real part between 1/2 and 1, the primes would be more squished together. The square root error correction term in the prime counting function comes from the hypothesis that all the zeros lie on the critical line, with real part = 1/2.
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10-18-2021 , 11:28 AM
Even ignoring the twin prime conjecture, nobody has proved that there is not a computable closed form function f(n) that simply returns the nth prime for all n.
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10-18-2021 , 11:39 AM
Quote:
Originally Posted by ecriture d'adulte
Even ignoring the twin prime conjecture, nobody has proved that there is not a computable closed form function f(n) that simply returns the nth prime for all n.
n=2.5. Your move.
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