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Procedure in chopping a pot with multiple all ins Procedure in chopping a pot with multiple all ins

07-05-2016 , 02:51 PM
I'd like to know the procedure on chopping an unclosed pot with multiple all ins.

This is a hypothetical situation. Three players all in in a 1/3 game with the two small stacks chopping the pot. It's 1/3 so you can chop down to the dollar.
  • Player 1 is all in for $25 and splits the pot
  • Player 2 is all in for $51 and splits the pot
  • Player 3 is all in for $1,000 and loses to player 1 and 2.
  • Pot has $25 in it and no other player has gone all in or is involved in the hand.
  • Assume player 1 is closest to the button.

This is what I think would happen but I'm not sure if it's correct.

Dealer takes $25 from each player for $75 total and chops it in half, $37 to player 1 and 2, and then giving the odd chip to player 1. Dealer then splits the main pot, giving $12 to player 1 and 2 and the odd chip to player 1. Player 1 has won a total of $51 ($37 + $1 + $12 + $1).

The dealer would then take $26 from Player 3 and give it to player 2 who wins a total of $75 ($37 + $12 + $26).

or would it happen this way:

Dealer takes $25 from each player and combines it with the main pot for a total of $100. Dealer gives $50 to player 1 and $50 to player 2. Dealer then takes $26 from player and gives it to player 2 who now has won $76 ($50 + $26).

I know it's only a difference of a dollar but the first example gives player 1 an extra dollar because he got two odd chips.
Procedure in chopping a pot with multiple all ins Quote
07-05-2016 , 02:59 PM
Is what you are saying is:

Pot $25 on the River
Player 1 shoves for $25
Player 2 shoves for $51
Player 3 calls and covers both players.

Player 1 and Player 2 have the same hand which beats Player 3
__________________________________________________ __


If so, the main pot is $100. Side pot is $52.

Player 2 gets side pot of $52 plus $50 (half of the main pot)
Player 1 gets $50 (half of the main pot)
Player 3 gets a "Bad beat bro"

But to your underlying question, the "standard" rule is that the same player can get multiple "odd chips" in split pots. The dealer settle each (side/main) pot in turn.

Say in your example there is a Player 4 that is all in for the first $25 pot and loses.

Then, second side pot is $52 and it goes to Player 2.

First side pot is $75 and Player 1 gets $38 and Player 2 gets $37.

Main pot is $25 and Player 1 gets $13 and Player 2 gets $13.

Last edited by AngusThermopyle; 07-05-2016 at 03:07 PM.
Procedure in chopping a pot with multiple all ins Quote
07-05-2016 , 03:00 PM
Why would you ever do it the first way? The main pot has $100 in it so why would you pretend it's a pot of $25 and a pot of $75 and split them seperately?

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Procedure in chopping a pot with multiple all ins Quote
07-05-2016 , 03:47 PM
Just do it the dummy way so everyone can see that it's correct. It takes like 10 seconds unless the people that think that takes too long pipe up and slow the whole process down by not letting anyone think straight and wasting even more time arguing about "an easier way".

Pull in the bets and makes the main and side pot right. Pay out the first sidepot giving the extra buck where it needs to go, then pay out the main pot giving the extra buck where it needs to go.

Everyone sees that it's correct. No one has any legit complaints.
Procedure in chopping a pot with multiple all ins Quote
07-06-2016 , 08:58 AM
Quote:
Originally Posted by psandman
Why would you ever do it the first way? The main pot has $100 in it so why would you pretend it's a pot of $25 and a pot of $75 and split them seperately?

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Agree.
Procedure in chopping a pot with multiple all ins Quote
07-06-2016 , 09:58 AM
Quote:
Originally Posted by DisRuptive1
Dealer takes $25 from each player for $75 total and chops it in half, $37 to player 1 and 2, and then giving the odd chip to player 1.

Dealer then splits the main pot
That 75 is part of the main pot. (as has already been mentioned)

But IF there are multiple side pots, and the same player wins the extra dollar multiple times, that is standard.
Procedure in chopping a pot with multiple all ins Quote
07-06-2016 , 10:52 AM
Not sure what all is going on here .. I read only 2 pots .. correct?

Always go 'backwards' .. start with the side pot ($52) and give it to P2, no splitting

Main pot ($100) is chopped between P1 and P2, $50 each, splitting.

I always try to keep anyone not in the 'last' side pot from showing their cards to prevent a mass mucking of cards which can lead to even more issues when chopping/shipping pots.

Now get really fancy here and drop the main pot down to $40 TOTAL .. where does the rake come from? GL
Procedure in chopping a pot with multiple all ins Quote
07-06-2016 , 11:26 AM
If you insist on not bringing in the final bets then the way to split the main pot and final bets is to take 1 chip (any odd denomination) out of the $75 on the side and move into the main pot. Now you can split it evenly
Procedure in chopping a pot with multiple all ins Quote
07-06-2016 , 11:41 AM
Quote:
Originally Posted by answer20
Always go 'backwards' .. start with the side pot
Good point. Side pot first 99% of the time.

The rare time the main pot is in the way of the pushing the side pot
and it's very clear who gets which pot, I will make it extra clear that,

"The side pot is yours. I'm gonna push the main pot first.".
Procedure in chopping a pot with multiple all ins Quote
07-06-2016 , 08:49 PM
Quote:
Originally Posted by answer20
Not sure what all is going on here .. I read only 2 pots .. correct?

Always go 'backwards' .. start with the side pot ($52) and give it to P2, no splitting

Main pot ($100) is chopped between P1 and P2, $50 each, splitting.

I always try to keep anyone not in the 'last' side pot from showing their cards to prevent a mass mucking of cards which can lead to even more issues when chopping/shipping pots.
Side pot first - as indicated above
Procedure in chopping a pot with multiple all ins Quote
09-28-2016 , 01:34 AM
Quote:
Originally Posted by answer20
Not sure what all is going on here .. I read only 2 pots .. correct?
Only one pot has been built (the main) but not closed. All 3 players are all in. Doesn't really matter how many side pots there are for my example, just that it hasn't been closed off.

Quote:
Originally Posted by answer20
Now get really fancy here and drop the main pot down to $40 TOTAL .. where does the rake come from?GL
I think I asked this question before and everyone in the thread was cool with prorating both pots.
Procedure in chopping a pot with multiple all ins Quote
09-28-2016 , 06:22 AM
Quote:
Originally Posted by DisRuptive1
Only one pot has been built (the main) but not closed. All 3 players are all in. Doesn't really matter how many side pots there are for my example, just that it hasn't been closed off.
There are 2 pots built and closed once everyone is all-in ... main has $100 and side has $52. Just because the chips may not have been pulled in doesn't mean that the pots aren't built/closed.

1) Dealer takes rake from $100 main ... now it's $94 (typically)
2) Dealer pushes side pot to Player 2 ... $52
3) Dealer chops main pot ... $47 each to Player 1 and Player 2

Not sure where the difficulty is here ... pull the chips in for each pot and start with the side when pushing them back out. GL
Procedure in chopping a pot with multiple all ins Quote
09-28-2016 , 08:00 PM
Quote:
Originally Posted by answer20
Not sure what all is going on here .. I read only 2 pots .. correct?

Always go 'backwards' .. start with the side pot ($52) and give it to P2, no splitting

Main pot ($100) is chopped between P1 and P2, $50 each, splitting.

I always try to keep anyone not in the 'last' side pot from showing their cards to prevent a mass mucking of cards which can lead to even more issues when chopping/shipping pots.

Now get really fancy here and drop the main pot down to $40 TOTAL .. where does the rake come from? GL

very simple, where I work (most of my city) main pot is large enough to achieve max rake, so take $4 from the main pot. If the rake is more in your place (find somewhere else to play) but assuming 10% rake to cap, take 4 from the main pot, and 10% up to appropriate cap from the side pot
Procedure in chopping a pot with multiple all ins Quote
10-05-2016 , 05:50 PM
Quote:
Originally Posted by answer20
pull the chips in for each pot and start with the side
Way too slow. Once everyone is all in, you no longer need to put chips into any more pots.
Procedure in chopping a pot with multiple all ins Quote
10-05-2016 , 07:49 PM
If a person only in the main pot fast rolls the nuts when action is complete what responsibility does the dealer have in protecting someone's claim to a side pot? What about as far as just good customer service would you expect?

As a personal example plo, 3 way all in on turn side pot between players 2 n 3, p1 fast rolls nuts after river. Dealer didn't say anything about the side action, as I was a the vacationing fish p2, n p3 being the local reg I felt somewhat slighted as I almost folded. Any just cause for that?

Last edited by chief pot; 10-05-2016 at 07:57 PM.
Procedure in chopping a pot with multiple all ins Quote
10-05-2016 , 11:20 PM
When the player who isn't involved in the side pot the dealer should say something along the lines of "hang on, we're still working in the side pot between seats X y and z." And the player should retrieve their hand and flip it back over before anyone else has acted.

In reality when a dealer (much like yourself) sees someone open up right away like they're about to scoop it'll take a few seconds to register they're only fighting for the main. Side pots are uncommon enough you should hopefully be able to know who you're up against. Dealer should say something, but it is ultimately up to the player to protect him/herself.

I wouldn't chalk it up to a dealer favouring a reg (ESPECIALLY a PLO reg).
Procedure in chopping a pot with multiple all ins Quote

      
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