Quote:
Originally Posted by moore_likely
In Joathan Little's Strategies for Beating Small Stakes Poker Cash Games he writes the following for calculating preflop pot size: You can figure the size of the pot by multiplying the last bet by three then adding in any additionnal money that is in the pot. On a 1/2$ table, he gives the example of two limpers, one raises to 10 and another raises to 26. So 26 x 3 + 10 + 2 + 2 + 2 + 1 = $95.
I'm honestly not sure why multiplying by 3 the last bet, but that's what's in the book.
I'm assuming there were 3 players to the flop? There's really no other explanation.
Here is an easy way to keep the pot amount
pf: multiply the raise amt. by the number of callers, and add the bb if he's not in the hand. (I usually leave out the $2 sb as this is easier to round off the pot plus it goes to the rake anyway)
Flop: (the bet amt) X (number of callers) + pf pot = turn pot
Turn: (the bet amt) X (number of callers) + turn pot = river pot
if you wana practice this, do it for all pots even if you are not involved (it's important to do this anyway so you can read what people are doing in relation to the pot)
It doesn't have to be accurate to the exact dollar. If you play 1/2, as long as it's within 5 bucks it's fine (until you can keep track of the exact number).