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Bobby's Breakroom - for gaming employee chatter + YTF appreciation. See restrictions in Post #1 Bobby's Breakroom - for gaming employee chatter + YTF appreciation. See restrictions in Post #1

09-13-2010 , 04:16 PM
Quote:
Originally Posted by youtalkfunny

"Payouts??", I asked in my best Jim Mora voice. "Don't talk about payouts. Payouts?? Are you kiddin' me? Payouts? I just want to win a hand! Payouts???"
well i thought it was funny
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09-13-2010 , 07:50 PM
Quote:
Originally Posted by metsjetsrangers
And 2+3, I believe that TECHNICALLY they are supposed to topple the stacks because you aren't technically supposed to allow players to count the pot when making a decision technically. However, if it is a heads up pot and big stacks are bet, I am sure veteran dealers would not get in trouble with leaving the stacks up...technically speaking of course.
What's the train of thought behind the bolded?
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09-13-2010 , 08:02 PM
Quote:
Originally Posted by Quadstriker
well i thought it was funny
hard to appreciate without the audio.
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09-13-2010 , 09:39 PM
Quote:
Originally Posted by Lottery Larry
hard to appreciate without the audio.
I audioized it in my head. With Jim Mora saying it as well.
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09-13-2010 , 11:38 PM
Quote:
Originally Posted by Quadstriker
I audioized it in my head. With Jim Mora saying it as well.
I retire, in complete jealousy of your mad skillz
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09-14-2010 , 12:28 AM
Quote:
Originally Posted by beermankirk
Am I the only one who thinks there should be physical job rquirements for a poker dealer?
I wonder about this too.

When I played live poker four days a week here in Colorado, I got to know the dealers pretty well. One guy was gone for a year and I asked him why. He had been rehabbing after having neck surgery and having blown out his right elbow, all from the strain of dealing. He said that injuries were pretty common among poker dealers. And he looked pretty healthy: he was about 6', 175#.

So how could a grossly overweight dealer hold up under the strain for more than a few years?
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09-14-2010 , 01:51 AM
Quote:
Originally Posted by Aabelno
I wonder about this too.

When I played live poker four days a week here in Colorado, I got to know the dealers pretty well. One guy was gone for a year and I asked him why. He had been rehabbing after having neck surgery and having blown out his right elbow, all from the strain of dealing. He said that injuries were pretty common among poker dealers. And he looked pretty healthy: he was about 6', 175#.

So how could a grossly overweight dealer hold up under the strain for more than a few years?
They probably have better mechanics. If you don't learn the right way, you are going to hurt yourself after you put some time in.
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09-14-2010 , 02:21 AM
Just watching bad dealers deal looks painful.

A good pitch looks great, feels great, and is overall great.
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09-14-2010 , 02:36 AM
Quote:
Originally Posted by Quadstriker
Just watching bad dealers deal looks painful.
No kidding. I cringe when I see dealer pitch with their hands against their chests.
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09-14-2010 , 05:52 AM
Quote:
Originally Posted by pfapfap
No kidding. I cringe when I see dealer pitch with their hands against their chests.
I think dealers who do this probably started in the pit dealing BJ and moved to poker. Got to pitch from up high when dealing Blackjack. Pitching the cards from down low felt weird to me when I pitched in to help in the poker room for a tourny.
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09-14-2010 , 06:18 AM
ive been assured that the payout of exactly 500 from 20 chips IS possible. outside bets only. all chips must be winning chips. 501 is defo possible (will post solution to that soon). 500 is the payout and does not include the 20 wagered.

ps: thx for efforts
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09-14-2010 , 10:56 AM
This is a very long problem, and it's been a few lifetimes since the SATs, but I'm working on it. I'm sure brute force would be faster, but this is more fun.

(Tho' I'm sure it'd be easier if I hadn't been drinking a lot at a home game last night... ow, my head.)
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09-14-2010 , 11:25 AM
Quote:
Originally Posted by pfapfap
This is a very long problem, and it's been a few lifetimes since the SATs, but I'm working on it. I'm sure brute force would be faster, but this is more fun.

(Tho' I'm sure it'd be easier if I hadn't been drinking a lot at a home game last night... ow, my head.)
Think about how the kitten must feel every single day?
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09-14-2010 , 11:46 AM
Okay, I suck. I can do the elementary stuff of getting it down to four variables and each as an expression of the other, but after that I keep ending up with 0=0, so I don't know what else to do. But here's some stuff if someone else wants a crack:

35a + 17b + 11c + 8d + 5e = 500
a + b + c + d + e = 20

a = 40/3 - 2b/5 - c/5 - d/10
b = 100/3 - 5a/2 - c/2 - d/4
c = 200/3 - 5a - 2b - d/2
d = 400/3 - 10a - 4b - 2c

As with most riddles, I'm sure there's an easy obvious answer here. Knowing that they need to be integers may be a key. Or maybe we just misunderstand the problem, since now he's saying outside bets. (Or maybe I don't know what outside bets means.)

EDIT: Tho' looking at these, it's impossible for them to be integers. I think the simple "always one fewer than a multiple of 3" answer may be correct, meaning that it can't be done.
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09-14-2010 , 12:04 PM
Have any of you dealers ever been falsely(I hope!) accused of cheating while playing where you work? That was a fun little experience I had recently.
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09-14-2010 , 12:07 PM
Here's another math riddle I think a 2+2er brought to my game. I tried it out in a casino and got into a mild disagreement with someone regarding the answer:

What's the probability of two people on the planet having the exact same number of hairs on their heads?
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09-14-2010 , 12:09 PM
Quote:
Originally Posted by pfapfap
Here's another math riddle I think a 2+2er brought to my game. I tried it out in a casino and got into a mild disagreement with someone regarding the answer:

What's the probability of two people on the planet having the exact same number of hairs on their heads?
Just two? Or at least two? Are the two random? Or do you have two specific people picked out?
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09-14-2010 , 12:10 PM
Quote:
Originally Posted by pfapfap
Here's another math riddle I think a 2+2er brought to my game. I tried it out in a casino and got into a mild disagreement with someone regarding the answer:

What's the probability of two people on the planet having the exact same number of hairs on their heads?
Two bald people = 100%? 0.o
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09-14-2010 , 12:23 PM
Take a range of possible number of hairs on people's heads. I doubt anyone has more than 6 billion hairs, and everyone would have greater than or equal to 0. So I would say that the probability is 100%. It would be impossible for every person in the world to have a unique number of hairs on their head.
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09-14-2010 , 12:27 PM
Quote:
Originally Posted by Aceium
Take a range of possible number of hairs on people's heads. I doubt anyone has more than 6 billion hairs, and everyone would have greater than or equal to 0. So I would say that the probability is 100%. It would be impossible for every person in the world to have a unique number of hairs on their head.
Ding ding ding!

My experience the one time I tried it was that my neighbor felt like it was impossible for it to be 100%, but couldn't figure out why, which just made her angry that she was being made to look stupid. But maybe your delivery will be better than mine.
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09-14-2010 , 12:32 PM
I'm still standing by my "two bald people" answer, but Aceium's reply was far more eloquently stated.
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09-14-2010 , 01:01 PM
OK, if we're doing puzzles, here's two:

1. Playing Omaha high, you are dealt 9333, including two spades. There are three hands you can make that would be the nuts. Name all three.

2. When I play hold'em, I never table my cards silently. I always announce what I have; I always announce when it's the nuts; and I never lie. So I might say, "I got the nuts, quad sevens," or, "I got the nuts, ace-high flush."

What is the lowest hand I can announce at showdown that could possibly be the nuts? Hint: It's lower than "ace-high flush". It's even lower than "Jack-high straight". But it's higher than any two-pair, because two-pair can never be the nuts.
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09-14-2010 , 01:06 PM
Question 1

Spoiler:
Board: 999xx, AKQJ10, cant think of the third!


Question 2

Spoiler:
3 of a kind 10's?
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09-14-2010 , 01:11 PM
Answers for ytf:

Spoiler:
1. Boards: 99942; 99345; AKQJTs
2. Set of Queens
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09-14-2010 , 01:24 PM
Quote:
Originally Posted by pfapfap

35a + 17b + 11c + 8d + 5e = 500
a + b + c + d + e = 20


EDIT: Tho' looking at these, it's impossible for them to be integers. I think the simple "always one fewer than a multiple of 3" answer may be correct, meaning that it can't be done.

35 = 11*3 + 2
17 = 5*3 + 2
11 = 3*3 + 2
8 = 2*3 + 2
5 = 1*3 + 2

If a + b + c + d + e = 20, then 35a + 17b + 11c + 8d + 5e would be 40 more than a multiple of 3.
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