This is a pretty common situation during the WSOP SNGs and elsewhere and I'm curious if anyone knows the math behind it or what this problem is even called if it has a name.

Completely hypothetically, imagine there is a $1,000 buy-in winner take all SNG with 10 players. Of those 10 players, 5 just buy-in for the $1,000.

Of the other 5, say all of them side-bet for $500, of those, 3 of them side bet amongst themselves for another $1,000 and of those, 2 side bet for an additional $2,000.

Player 1 = $1,000
Player 2 = $1,000
Player 3 = $1,000
Player 4 = $1,000
Player 5 = $1,000
Player 6 = $1,000 + $500 sidebet
Player 7 = $1,000 + $500 sidebet
Player 8 = $1,000 + $500 sidebet + $1k sidebet
Player 9 = $1,000 + $500 sidebet + $1k sidebet + $2k sidebet
Player 10 = $1,000 + $500 sidebet + $1k sidebet + $2k sidebet


The people that just buy-in to the game, all else equal, have a sizeable advantage because they can simply play to win. Meanwhile, the more heavily stacked the sidebet is amongst the other players, the more they have ICM considerations to think about limiting the types of plays they can make. However, obviously, the side-bettors may feel they have an edge in the game great enough to overcome the ICM differential loss. But nonetheless, there is a theoretical $loss they are free-market electing to do right from the start all else equal.

So my ultimate question is this: Is there a way to somewhat easily compute the final dollar values of everyone's registration when the game starts all else equal? Or do any of the ICM calculators handle this kind of thing? (I've never used one before).

Apologies if this kind of question can't be answered, it's well beyond my pay grade to even know