tried looking this up got lost. QQ3 flop, 9 handed table, im headsup at the flop with KQ, how often will i be against AQ, 2 folded and villian put me in

Given that you're asking this, I'd say about 99%... The other 1% the villain has 33

-d

Thanks man! Figured it wasn't worth thinking about. So its just an auto fold since we really had no history. cheers

Sorry, I didn't mean to sound like an ahole. But it sounds like this is more of a strategy question than a probability question.

You need to narrow the villain's range. You can help do this by answering some questions. Was there a preflop raise? Who made the raise? What are the stack sizes? How has the villain played so far? What is the villain's perception of you, etc. Without knowing this stuff, the villain's range can be any two cards.

If you bet and villain raised, well, how many hands would make sense?

-d

Know i don't know what your talking about i had no intrest in any of what you just said

The notion that you really need to know what is villain’s likely range and other factors is certainly valid. But, as a conservative (very likely a very poor and low estimate) of villain having AQ assuming he is playing any two cards, the probability is C(1,1)*C(4,1)/C(47,2) = 4/(47*23) = 0.37%.

Okay, let’s be a bit more realistic. Assume villain is a tight player whose range as played is {TT+, AQ+, KQs). That’s 30 +32 +4 = 66 combos. But with the given flop and your hand, that reduces to 21 + 16 + 1 = 38 combos, at most (possibly can’t have KQs). So of those 38, only 4 are AQ, indicating there is about a 10.5% chance he has AQ.

So, make a stab at what you think villain’s flop-shove range is and do your own analysis. Hopefully, my example provides enough guidance.

Thank You Sir! probably replace AQ+ with 10 Q+ and KQs with Q9s+