Quote:
Originally Posted by nath
Thanks. I need to apply this to a game with a bigger deck, so refresh my memory:
C(N,K) is calculated as N! / (K!(N-K)!), is that right? So the above is
(50! / (3!*47!)) / (52! / (5!*47!))
?
I did it this way with N = 52 and K = 5 and got the same answer as you, so I think I did it right.
Yes, you're right, although most calculators have a built in function for C(N,K). In google search you can do "N choose K."