Quote:
Originally Posted by whosnext
We have had a few recent threads on this topic. I will summarize the results from those threads. Many members of this forum have contributed to these results. As per usual, these results assume all players go to showdown on all deals.
(1) Quads of any rank in NLHE using a pocket pair (one player)
= 13*C(4,2)*C(48,3)*C(2,2) / C(52,7)*C(7,5)
= 1,349,088 / 2,809,475,760
= 0.000480192
which is approx once every 2,082 deals.
(2) Royal Flush in NLHE using both hole cards (one player)
= 4*C(5,2)*C(47,2)*C(3,3) / C(52,7)*C(7,5)
= 43,240 / 2,809,475,760
= 0.000015391
which is once every 64,974 deals.
(3) Straight Flush (excluding royal flush) in NLHE using both hole cards (one player)
= 4*9*C(5,2)*C(46,2)*C(3,3) / C(52,7)*C(7,5)
= 372,600 / 2,809,475,760
= 0.000132623
which is approx once every 7,540 deals.
I would highly recommend that you wait for confirmation of these results before utilizing them.
Also, the above results are for one player at a NLHE table. For N players at a NLHE table, you would need to multiply the above probabilities by N (which are very very close to the actual probabilities).
I/we will turn our attention to your second question in a subsequent post.
I use a slightly different method.
Quads:
Pr(pocket pair) = 1/17. Assume w.l.o.g. black aces.
conditional Pr(Ah on board) = 5/50
conditional Pr(Ad on board) = 4/49
Probability = 20 / 41,650 = 1 / 2082.5
Royal:
Pr(royal cards) = 20*4 / 52*51 = 20 / 663. Assume w.l.o.g. AsKs.
conditional Pr(Qs on board) = 5 / 50
conditional Pr(Js on board) = 4 / 49
conditional Pr(Ts on board) = 3 / 48
Probability = 1 / 64,974
Our solutions match up for quads and royals, computed 2 different ways. Seems unlikely we are both wrong.
There is no such quick / dirty / easy way to figure out the probability of a straight flush so I'm lazy enough to just trust you