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calculating variance calculating variance

12-08-2017 , 05:47 PM
Hi, I am reading the MOP book and it says calculate the variance of a coin flip like this :

V = (1/2)(1-1/2)²+(1/2)(0-1)²
V = 1/4

But the previous page it calculates the variance of betting 1$ on a coin flip like this :

V=(1/2)(1-0)²+(1/2)(-1-0)²
V= 1

I understand in the first case the EV is zero, betting 1$ for 1$, in the second case the author seems to just think about variance of coin flip without referring to a bet so says EV is 0,5.

However I feel like the results don't correlate. For example if you flip 100 coins, Ev is 100 coin flip in one case but 25 in the other case.

Does anyone understand this part ? Thank you!
calculating variance Quote
12-08-2017 , 09:09 PM
I assume your first equation was supposed to be
V = (1/2)(1-1/2)²+(1/2)(0-1/2)²
This equation seems to be the variance in dollars for a situation where you win a dollar when it's heads and lose nothing when it's tails

The second equation
V=(1/2)(1-0)²+(1/2)(-1-0)²
would be the variance in dollars for a situation where you win $1 when it's heads and lose $1 when it's tails. It could also describe the variance in "wins - losses" or "net wins" which is the same thing.
calculating variance Quote

      
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