Quote:
Originally Posted by dantheman_05
Certainly one of the many different types of mathematics must be able to handle this problem more elegantly than counting ??
Expanding on NOG’s answer and written somewhat in jest:
Let N be the total number of outcomes of AA vs KK assuming all hands go to showdown.
Let Na be the number of outcomes where AA wins
Let Nk be the number of outcomes where KK wins
Let Nt be the number of outcomes which tie
Na + Nk + Nt = N
Then P(AA "wins") = (Na + Nt/2)/N