hmmm okay, maybe post your math and I'll take a look.
try your best to follow mine, I know this can be a bit tough to follow
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to simplify the math and because I will do just about anything to avoid matrix algebra lets assume we either get folds or one caller*
V calling range is TT+,AKo, AQs call it R1
AKo Vs R1 has 42.87% equity
when we win the pot by shoving we get 9.1bb = (2.2bb * 3 + SB + BB + 1bb for anti)
when we get called the total pot size is 87.9bb = (41bb * 2 + 2.2bb*2 + SB + 1bb for anti)
now we declare a variable x which is the % of time we get folds
to break even 0=x*9.1+(1-x)(42.87%-57.13%)(87.9) EQ
1)
simplified: 0=x*9.1-(1-x)(14.26%)(87.9)
0=(the percentage of folds * the +BB from folds) - (the percentage of time we get called times our expected EV when called)
x=0.6272
meaning so long as we get 42% folds we are break even and if we get more than that we are making money.
for giggles lets give V calling range just JJ+ AK = R2
Vs R2 we have 39.785% or losing (-) 20.430% EQ
1) becomes
to break even 0=x*9.1-(1-x)(0.20430*87.9)
x=0.6637 or 66.37% folds
if we weaken V range we quickly get to the point where AK is break even or + EV at this point it just starts printing money
I hope this helps
*given how tight our calling ranges are I believe this is a fair assumption. If you want to see for yourself we have 24% equity Vs 2 players with range R1 and the odds of us being called twice is probably about 1/10
Last edited by Captain-Hindsight; 05-20-2019 at 09:33 PM.