Programming homework and newbie help thread
01-16-2015
, 08:08 PM
doh 
ty
edit: hmm still getting the same thing ;[ both c/f computing temps correctly, but the 'c' (and only 'c') getting 'Invalid input' as well.
it's the same code as above except replacing the aforementioned 2nd 'if' with 'else if', but here it is anyway:
tyedit: hmm still getting the same thing ;[ both c/f computing temps correctly, but the 'c' (and only 'c') getting 'Invalid input' as well.
it's the same code as above except replacing the aforementioned 2nd 'if' with 'else if', but here it is anyway:
Code:
float main()
{
float temp;
char convert;
cout << "Enter a temperature: ";
cin >> temp;
cout << "Press 'c' to convert Fahrenheit to Celsius. Press 'f' to convert Celsius to Fahrenheit. ";
cin >> convert;
if (convert == 'c')
{
float ftemp, ctemp;
ftemp = temp;
ctemp = (ftemp - 32) / 1.8;
cout << "The Fahrenheit temperature (" << temp << ") is \"equivalent\" to the Celsius temperature (" << ctemp << "). ";
}
else if (convert == 'f')
{
float ftemp, ctemp;
ctemp = temp;
ftemp = ctemp * 1.8 + 32;
cout << "The Celsius temperature (" << temp << ") is \"equivalent\" to the Fahrenheit temperature (" << ftemp << "). ";
}
else
{
cout << "Invalid input. ";
}
}
01-16-2015
, 08:49 PM
Quote:
doh ty
edit: hmm still getting the same thing ;[ both c/f computing temps correctly, but the 'c' (and only 'c') getting 'Invalid input' as well.
it's the same code as above except replacing the aforementioned 2nd 'if' with 'else if', but here it is anyway:
tyedit: hmm still getting the same thing ;[ both c/f computing temps correctly, but the 'c' (and only 'c') getting 'Invalid input' as well.
it's the same code as above except replacing the aforementioned 2nd 'if' with 'else if', but here it is anyway:
Code:
float main()
{
float temp;
char convert;
cout << "Enter a temperature: ";
cin >> temp;
cout << "Press 'c' to convert Fahrenheit to Celsius. Press 'f' to convert Celsius to Fahrenheit. ";
cin >> convert;
if (convert == 'c')
{
float ftemp, ctemp;
ftemp = temp;
ctemp = (ftemp - 32) / 1.8;
cout << "The Fahrenheit temperature (" << temp << ") is \"equivalent\" to the Celsius temperature (" << ctemp << "). ";
}
else if (convert == 'f')
{
float ftemp, ctemp;
ctemp = temp;
ftemp = ctemp * 1.8 + 32;
cout << "The Celsius temperature (" << temp << ") is \"equivalent\" to the Fahrenheit temperature (" << ftemp << "). ";
}
else
{
cout << "Invalid input. ";
}
}
Code:
if (convert == 'c')
Code:
if ('c' == convert)
Last edited by adios; 01-16-2015 at 08:57 PM.
01-16-2015
, 09:08 PM
Quote:
The code is right, next step is to use argc and argv as input parameters to main. In that way the user has the option to enter temperature and/or temperature type on the command line. Although I know at Intel and from what I've heard it is the same at Microsoft, instead of
they do this:
In that way if it is coded with = instead of == the compiler will generate an error.
Code:
if (convert == 'c')
Code:
if ('c' == convert)
i'm confused with part of your comment though, isn't the user already entering temperature/type on the command line with the current code?
01-16-2015
, 09:51 PM
ConvertTemp 40 C
The user isn't prompted because the proram reads its inputs from the command line. That is the idea.
01-17-2015
, 11:54 AM
Your current code works fine for me. I think you must have a build problem, like others have suggested. You must be running a stale executable. Try to find any copies of the built executable and delete them all. What IDE are you using? Visual Studio?