char x;
std::cin >> x;
std::cout << x;

// This is the Simultaneous Equation Solver program (SimultaneousSolver.cpp)
// This program will solve a pair of linear equations in two variables x and y
// Written by: Chase Banta
// Date: 11 April 2013
// Sources: None

#include <iostream>
#include <string>
#include <iomanip>

using namespace std;

int main() 
{
	
	// Here we declare our variables.  I am declaring everything
	// doubles so that my final x and y values will display with
	// decimals. Code will be used to make sure the doubles appear
	// as ints where the assignment instructions indicate they should.
	double a1; 
	double b1;
	double c1;
	double a2; 
	double b2; 
	double c2;
	double x; 
	double y;
	bool a;
	bool b;
	bool c;

	// This section fixes the float value of our 
	//...numbers to the value in 'setprecision'
	cout << fixed << setprecision(2);
	
	// This section creates dialog between the user and the computer
	//...where the user inputs values for the solver to work on
	cout << "Welcome to Chase's Simultaneous Equation Solver." << endl;
	cout << "Please enter a1, b1, c1 (separated by spaces): ";
	cin >> a1 >> b1 >> c1; 
	cout << "Please enter a2, b2, c2 (separated by spaces): ";
	cin >> a2 >> b2 >> c2;
	cout << "The solution of the equations:" << endl;
	
	// Using static_cast below allows us to have an output that is appropriate for
	//...integers per the examples on the instructions.
	cout << static_cast<int>(a1) << "x + " << static_cast<int>(b1) << "y = " << static_cast<int>(c1) << endl; 
	cout << static_cast<int>(a2) << "x + " << static_cast<int>(b2) << "y = " << static_cast<int>(c2) << endl;

	// Arithmetic for Cramer's rule
	x = (c1 * b2 - c2 * b1) / (a1 * b2 - a2 * b1) ;  
	y = (a1 * c2 - a2 * c1) / (a1 * b2 - a2 * b1) ;

	// Below I have created conditional statements and assigned
	// them to the values of a b c. I opted to do this because it
	// made it easier for me to organize the last "if" statement

	// a is the case where at least one of the users string of inputs is 0 0 0 and two lines do not exist. 
	a = ((a1 == b1) && (b1 == c1) && (a1 == 0) || (a2 == b2) && (b2 == c2) && (a2 == 0));
	// b is the case where the lines are parallel.
	b = ((a1 * b2 - a2 * b1) == 0) && (a == false) && (((a1 == a2) && (b1 == b2) && (c1 == c2)) == false);
	//c is the case where the lines are the same.
	c = (a1 == a2) && (b1 == b2) && (c1 == c2) && (a1 != 0) && (b1 != 0) && (c1 != 0);
	
	// appropriate outputs based on how the conditional statments evaluate
	if (a)
	{
		cout << "is nonexistent because you have not entered values that create two lines." << endl;
	}
	if  (b)
	{
		cout << "is nonexistent because the lines are parallel." << endl;
	}
	if (c)
	{
		cout << "exists at infinitely many points because the lines are the same." << endl;
	}
	if ( (a == false) && (b == false ) && (c == false))  
	{ 
	cout << "is x = " << x << " and y = " << y << endl;
	}
	cout << "Thank you for using Chase's Simultaneous Equation Solver.";

	// This section ensures the program doesn't exit until the user is ready
	getchar();
	getchar();
	return 0;
}

>> print('{:.3}'.format(7/3-5/3-2/3)
1.1e-6

if (a1/b1 == a2/b2 && c1/b1 == c2/b2) {
     cout << "something about the same lines";
}
if (a1/b1 == a2/b2 && c1/b1 != c2/b2) {
     cout "something about parallel lines"
}