Hi.
How PT or HM calculate $EV and cEV at HUSNG?
This is situation:2 players;500 chips each at beginning; buy-in:5$
After 10 hands, player A has 750 chips and player B has 250 chips.
At hand #11 they go allin preflop (allin #1). Player A has AA, player B has KK (Player A vs Player B(aprox.):83%vs17%).
Player B wins this hand. They have now 500 chips each. After 25 hands, player B has 900 chips and player A has 100 chips. At hand #26 they go allin preflop(allin #2). Player A has KK and player B has AA. Player A wins this hand. Now player A has 200 chips and player B has 800 chips. After 10 next hands player B wins a sng without any allin following(no change of EV). How does PT or HM calculate chips cEV and $EV in this situation?


Is it like this?
allin #1:
cEV:500 chips *0.83=+417 cEV: player A
$EV: Allin was for 500 chips, which is 500/1000(all chips=10$)=5$; 5$ *0,83= +4,17$
Allin #2:
200 chips *0.17=34:200-34=-166 cEV
$EV: Allin was for 200 chips, which is 200/1000(all chips=10$)=2$:-1,66$

Player A cEV after this HUSNG is 417 -166=251cEV and Player A $EV after this HUSNG is 4,17$-1,66$=2,51$.
Player B cEV and $EV are exact opposite of player A: -251cEV and -$2,51.

Is this correct?

Or is it done in some different way?

I can not check this myself(at playing poker online). I used 14 day-trial period of both some time ago already. I only play poker for fun from time to time (rarely), but really curious about this.

if someone folds or calls with no cards to come that is are also included in ev, for example, both start with 500 chips, player A minraise, bets 40 otf, bets 80 ott, bets 160 otr and player B folds river, thats +160 ev chips for A. If player B calls river and wins thats +320 cev for player B.
For all in pots with cards to come seems you have calculated correctly.

Thanks for reply.

Just to clarify. Let us say like in your case player B folds river and that is +160 cEV chips for A, because 40(as of minraise starting blinds are 10/20)+40+80=160?

Is it possible for you or somebody else that you tell me exact cEV and $EV of player A and B from my example of game after it is finished? I do not want to write something wrong, so I rather just ask for right numbers.

jup
Its not possible to calculate ev with missing hands.

But for those 2 hands looks right, but 500*0,83=415, dunno how you got 417.
than you calculate how much 1 chip is worth, dont forget rake, so lest say buy in is 4+1 than 1000 chips = 8$ so 1 chip = 0.008$
417*0.008=3.336
Same for 2nd hand

Thanks so much for reply.

How is it not possible to calculate ev without missing hands?

My thinking here:
Example no.1(beginning of game): Hand #1 Person A wins 40 chips, which is 40+ cEV, next hand A wins 60 chips;= 100 chips plus for player A after 2 hands.; +100 cEV for player A
Example no.2(beginning of game): Hand #1 person A wins 140 chips, which is 140 +cEV, next hand person B wins 40 chips= 100 chips plus for player A after 2 hands.;+100 cEV for player A

In both examples player A gets same cEV (since there was no allin cEV is the same as chips here). Does not really matter how? After all, there was no allin? Or am I missing something? What?


You are right about 500*0,83. My mistake. Correct number is ofcourse 415.

Got reply from support PT: How it is done (if anyone else is interested): https://www.pokertracker.com/guides/...lation-example