Quote:
Originally Posted by bigmuff
Not sure how much more simple I can make this. Lets say the house collects 35 bb/hr. If the winners pay 10bb in rake then the losers pay 25bb in rake. Show me where in RP's formula he accounts for 10bb the winners pay in rake. Using your thermodynamics example it seems like it just disappears.
I don't know how much more simple to make this without drawing you a picture with arrows.
First off, I dug up RP's original post:
Quote:
Originally Posted by Richard Parker
Doubt it.
1 crusher = 10bb/hr
2-3 OK player = 8bb/hr combined?
Rake/jackpot = 30bb/hr
Tip = 5bb/hr
10 + 8 + 30 + 5 = 53bb/hr
53bb divide by 5 - 6 players = 10bb/hr?
So questions are:
1. Are there consistently 5 to 6 players losing at 10bb/hr at the table?
2. Is there really one crusher at the table raking in 10bb/hr?
3. Are there 2-3 guys not counting toward the table loss rate?
IMO, I can't see rooms with a lot of players losing 10bb/hr, so the average loss rate must be lower. If average loss rate is lower, then there is less money to be won.
So are there really many players who are crushing it on regular basis, or even just breaking even on regular basis? I think not.
Now for my model, "conservation of manies":
Draw a control volume around the table. Winners take X bb/hr out, dealer takes Y bb/hr rake/tips out, fishes put Z bb/hr in.
X + Y - Z = 0
Can we agree on this simple statement?
At this point we don't care what's happening to the money when it's on the table.
Now we add RP's calculations:
X = 10 bb/hr + 8 bb/hr for 4 total players (8 bb/hr combined for 3p)
X = 18 bb/hr
Y = 30 bb/hr + 5 bb/hr for Rake + tip
Y = 35 bb/hr
So what is Z? The total loss rate.
Z is just X + Y = 18 + 35 = 53 bb/hr.
This is the number of new chips that need to be placed on the table to sustain the rake and winrates of the winners.
For 5 players that's 53/5 = 10.6 bb/hr/player.
These are rake adjusted win and loss rates. This is what a player's
pocket feels. When they write down their results this is the number they use (or what shows up on their ATM receipt).
Is the average fish consistently peeling off $20/hr at a $1/2 game?
Based on how often I see players reloading, I don't actually think that's not all that far off.
So that's all rake adjusted, and we can agree on that, right?
There's no money going missing? It's all either lost by the fish, raked, or won by the crushers.
Now lets account for rake. But we need a model. Larger pots are raked more, so the size distribution of pots a player plays will effect how much rake is taken out of the hands that he's involved in (win or lose). This is a pain to try to account for, so lets simplify and say that in the long run it all evens out and everyone pays the same fraction of the rake. (In general I think bad players tip more, as they peel off redbirds for big and sometimes small pots, while crushers tend to stick to a dollar all the time.)
We've got 9 players at the table, 4 winners and 5 losers. 35 bb/hr in total rake/tips. 3.888 bb/hr each.
So the crusher that takes 10bb/hr off the table *wins* 13.888 bb/hr, and pays 3.888 bb/hr in rake, to net his 10 bb/hr.
The marginal winners each win 8/3 + 3.888 = 6.555 bb/hr before rake.
The losers net a loss of 10.6 bb/hr, so -10.6 bb/hr + 3.888 bb/hr = -6.712 bb/hr
So the losing player loses 6.712 bb/hr because he's bad at poker, and 3.888 bb/hr due to the rake.
While the crusher wins 13.888 bb/hr because he's such a bad ass, and still pays 3.88 bb/hr in rake.
With no rake the winners would win more, and the losers would lose less. But the money's still conserved, adding up the win/loss rates in a game without rake/tips:
13.888 + 3*6.555 - 5*6.712 = -0.0070 (close enough to zero with the roundoff).
There's no double or mis- counting here. Everything adds up. You could argue that the rake distribution should be shifted, but then that's another discussion.
This guy gets it, although the sign convention on the rake paid by losers is inconsistent:
Quote:
Originally Posted by t_roy
We don't know and it doesn't matter.
Win Rate (amount won from players - rake paid) + Total Rake (Rake paid by winners + Rake paid by losers) = Loss Rate (amount lost to players - rake paid)
or
Profit taken off the table by winners + Amount taken off the table by dealer = Amount lost on table by losers
I don't know how else to break it down.