Quote:
Originally Posted by curdanol
I played with a guy tonight who went all-in blind like 20 times. Got me wondering what the weakest hand is that's a favorite against any two cards. Feels like it should be somewhere in the T9 ballpark. Anyone know the mathematically correct answer? If someone goes all-in blind and you're in the big blind (with no one else in) and you're willing to take the smallest +EV edge, what can you call with?
Assuming you’re the last person to act, everything that has 50% equity or more vs 100% range is:
22+
A2+
K2+
Q2s+/Q5o+
J5s+/J8o+
T7s+/T9o
98s
97s has 49% equity and 98o has 48% equity
This range doesn’t take into account stack depth or rake. So I listed anything from 50%+, but if this was being done in my 2/5 game with 1k cap, 5+2 rake, I would actually want anything that is 50.4%+, as (1000+7)/2000=.5035, or 50.35%, which would be the break even point to cover the rake. The higher max stack depth compared to rake brings the desired percentage close to 50%, while lower max stack depth would be the inverse. A 1/3, 500 max, 6+2 rake, would need 50.8% equity to break even.
I don’t recommend playing pit games, but Ultimate Texas Holdem, and similar games, where you are playing solely against the dealer and you can see all 5 cards, you start to see this realization about the above range, specifically how high card matters much more than just about anything else. Ax and Kx are max jams pre in that game because of it. The game is more nuanced because of the betting structure, but you can easily see how the above range generally applies with some tweaking to account for bet structure and house edge.
Last edited by johnny_on_the_spot; 11-04-2022 at 10:12 AM.