Quote:
Originally Posted by AAJTo
I'm assuming if V2 can have JTo 98o 97o and 65o in this spot we are still getting too good of a price to fold someone correct me if I'm wrong.
One problem--and what makes this so tough--is that on those occasions when we beat V2, we also still have to beat V1.
So let's give V1 a range of TT/99/88. That means in the abstract he has us beat half the time. (I'm giving him all TT to account for other de-weighted overpairs.)
HOWEVER, if we are beating V2 it's because V2 likely has 98. And that blocks V1 from having a better set than us.
So if V2 has a straight (or bigger set), it doesn't matter how often V1 beats us because we lose anyway. But when V2 has 98, now V1 beats us 25% of the time. And when V2 has 33, we're losing to V1 half the time.
So it REALLY matters here whether V2 can have 98, as we not only beat that hand but that hand blocks V1 from having us beat at the same time. And it really matters how much of V1's range beats us, because we have to beat both, so we're multiplying decimals, which makes them smaller quite quickly.
Now let's say V2 can have all 98. That's 9 combos, to go with 3 combos of 33, against 16 combos of 65 and 6 combos of better sets. Looks like if this is correct we're good against V2 12 times out of 34, or 6 out of 17, which looks good UNTIL you multiply that by the chance we're good against V1. Works out like this:
(9/34)(3/4) + (3/34)(1/2) = 27/136 + 3/68 = 33/136 ~ 24.26%
But ranging V2 wrong (e.g. taking a bunch of the 98 out of his range if we think he only plays 98s or doesn't play top 2 like this) REALLY screws with this computation. So I think it's really close...
EDIT: So actually if we think V2 can show up with both the top and bottom end of the straight this turns into a clear fold!
Last edited by CallMeVernon; 06-21-2023 at 11:18 PM.