Quote:
Originally Posted by ChaosInEquilibrium
Yeah, of course we size up on turn if one of V1-V3 calls.
$100 is nothing to sneeze at, of course any line is profitable with 44, but I’m claiming there’s another line that earns more (assuming that flop jam generates more than 20% fold equity from Kx relative to lead turn/lead river). That’s all. My assumption could be off, but the math is correct given the assumption.
OK, let's take a closer look at this.
There are, given your assumptions, 3 ways this breaks down. If you think my premises are off somewhere or not in line with your original assumptions, let me know.
Scenario 1: We jam flop (or do what JayKon did, which is essentially equivalent). All open-enders fold, and V6 calls with probability X. Let's assume that when this happens, we always win the current pot of $285, plus V6's stack anytime he calls it off.
In this scenario, our EV is
285 + 160X.
Scenario 2A: We call flop, and everyone else folds because no one had an open-ender. Your assumption is that when this happens, we always get V6's stack by breaking up the bets so that each is too small to fold to.
In this scenario, our EV is 285 + 160 =
445.
Scenario 2B: We call flop, and one open-ender calls behind us, putting an extra $65 in the pot. We then jam all turns (let's simplify the math by ignoring board pairs, which I think doesn't matter much because some of those board pair outs are blocked by some of the Vs who called already). If the open-ender misses, let's assume we isolate V6, who stacks off to us with probability X (I think this is reasonable because it's the same bet size as in Scenario 1).
Let's put the probability of the open-ender hitting at 8/42, or 4/21. I'm using 42 because we can remove the flop (3), our cards (2), V6's cards (2), the open-ender itself (2), and one but maybe not both of V4's cards (1).
So 17 times out of 21, we win 285 + 65 + 160X = 350 + 160X.
4 times out of 21, we lose our flop call, plus a turn bet of 110, to the open-ender, so -175.
Overall, the (simplified) EV of Scenario 2B is (17/21)(350 + 160X) - (4/21)(175) ~
250 + 129.52X.
Now, your assumption is that 2A and 2B both happen half the time, so the overall EV of calling, under these assumptions, is
(.5)(445) + (.5)(250 + 129.52X) =
347.50 + 64.76X.
From here we can consider
285 + 160X = 347.5 + 64.76X
95.24X = 62.5
X = 62.5/95.24 ~ 65.62%
So this is higher than I would have guessed (even though it is quite a bit lower than your claimed 80%), but it does appear that under your assumptions, slowplaying is likely better. Also, the simplifications we made are all biased against slowplaying--the board will pair sometimes, leaving the straight draws drawing dead.
There are, however, multiple issues that have not been raised yet:
1. If we jam, anyone with an open-ender is looking at calling 175 to win 285+175 = 460 (and that assumes V6 always folds after the cold call). With those odds, shouldn't open-enders be calling!? Does that in fact mean that if an open-ender will fold to a jam, that is extremely good for us? Doesn't that also mean that we would rather jam now in case the board does pair on the turn?
2. The above computations carried the assumption that if we get heads-up with V6 for the side pot, he'll call off 2 pieces. Maybe V6 is smart enough to know that if we make a tiny bet on the turn, he'll be faced with a decision for his stack on the river. That means it's possible that V6 stacks off with probability X no matter how we play it. If that is true, then that is a big point in favor of jamming, since now slowplaying when no one will call behind us has zero advantage.
3. The assumption that we are only ever up against one open-ender is faulty. Each player's hand is roughly independent of the other ones. So if we are assuming that 50% of the time there will not be an open-ender, we're implicitly assuming that each player's (V1-V3) chances of NOT having one is approximately 2^(-1/3), or about 79.37%. Let's simplify and say that about 20% of each player's range is open-enders. That means there's a 64/125 chance (about half) of no open-ender, a 48/125 chance that there's exactly one, but a 12/125 chance--just under 10%--that there is more than one. And in that case (assuming they have different open-enders, which I guess happens about 5% of the time under these assumptions), EACH open-ender steals EV from us with a call, and we have to dodge 14 outs on the turn when we slowplay instead of 8. That does somewhat drag down the EV of slowplaying--though probably not enough to really matter.
4. It's also possible that an open-ender that we invite into the pot will turn a flush draw--and with the pot as big as it is, giving that hand a +EV call on the turn, dragging down the EV of slowplaying even more. (EDIT: Maybe an open-ender already has a +EV call on the turn as long as the board doesn't pair!?)
So overall, I guess this spot is a shining example of the old adage that the most heated debate takes place over the closest spots that probably don't have much impact on our winrate.