Quote:
Originally Posted by robert_utk
Ahh, yes. Are we to assume how many players are seated at the table? This will be part of the solution, and if all have antes it gets quite interesting!
You can use the notation you were using for an in determinant amount of callers.
Each caller is dependent on how many callers in front of them and how many potential callers behind them because they all contribute to how often they have to win.
Basically player n can have any number of calling scenarios where the number of callers varies from 0-(n-1).
Luckily if player n doesn't have n-1 callers in front of her, her calling decision reduces to the same decision as a player in the spot (n-(n-(k+1))) where k is the number of callers in front of player n.
So for example say 9 players total with 6 callers in front. Player 9's calling decision is the same as player (9-(9-(6+1))) = 9-2 = 7 when all players have called before. Yeah I think that should be right.
Almost seems like there is a series construction in there, but not sure how you account for callers behind.