Can the value of position be quantified? - Page 2 - Poker Theory

If the model, or bot, you are working with is too aggro opp, why not just remove the weakest flop continuing combo or two from that range and let it stay aggressive with the stronger range? One or two check-folds or check-call instead of c-bet or check-raise.

Ultimately frequencies are the summation of the collective actions assigned to each combo contained within that range. If you are wanting to account for position, especially on the turn or river, it boils down to combos, imo.

Because that would be cheating. I'm looking for a method to adjust using theory instead of manual adjustments

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10-23-2018 , 03:24 AM

#27

abanger

centurion

Join Date: May 2005 Posts: 101

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Originally Posted by getmeoffcompletely

You can do it with a solver, just plug in identical ranges and allow every strategic option. Remember a solver does not care about "initiative", the only difference will be that one player will be IP and another OOP. Doing this for IP open vs BB flat it turns out IP gets ~55% of the pot and BB ~45%.

We can say that for the average situation of 100bb stacks position is worth ~5% of the pot (without any range asymmetry considerations). As stacks get shorter it becomes less and less valuable. At around 5bb stacks position has no value.

Is saying position is worth 5% of the pot the same thing as a 10% edge?

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