The preflop ranges are the same. And evaluating overall EV at root node.
Just so it's clear what I'm trying to do: I solve down a spot to high accuracy, use one size OTF, and lock IP's strategy so he cannot re-adjust even if I re-solve the tree. IP's play is static, fixed. I also nodelock OOP OTF and come up with a new flop strategy (simply adjusting frequencies, overall range stays the same).
My hypothesis was that there should be minimal EV loss, since IP is playing a strategy approximated to the Nash equilibrium strategy, whereas OOP isn't playing 'GTO' anymore. My understanding so far was that if I solve down a sim to low exploitability, then using this strategy will never lose EV against any other possible strategy. Since it's OOP that has deviated from the pair of equilibrium strategies for this spot, I thought it would be OOP that loses some small amount of EV. (maybe my understanding here is off?)
After changing OOP strategy and nodelocking IP OTF (which causes IP to play 'static' from the flop onwards, meaning every other node past the flop is also unchanged) I get this EV difference:
and at the bottom the exploitability:
I'm not really sure what I could be overlooking here.
@Tombos21
I calculated results because I wanted to compare the EV when IP plays the >old< strategy against OOP's >new< changed strategy. So I don't need to re-solve here as I don't want to find a new equilibrium. I calculate results to just quickly find the EV difference. Once I re-solve allowing IP to change his strategy (unlocking the flop), then a new equilibrium is reached, and IP actually gains a little bit of EV due to OOP deviating.
original 'GTO' strat:
OOP nodelocked betting range:
I won't flood with screenshots, but IP's strategy is the same in both, for every node. Re-solving would change this, and then IP's EV jumps up to around 218 when I do this. But my question is why does IP lose significant EV whilst using the original equilibrium against a new OOP strat.