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Runner runner straight maths Runner runner straight maths

09-05-2024 , 10:32 AM
Hey! Resident fish here! Trying his hardest

I’m on this page of my post flop colouring book, where it discusses run out situations

Hero: JdTd

Board Ah7s4c

How often will I hit runner runner straight
(KQ&98)

So I understand I have to work out how often it does NOT happen for turn and river (= N)
(Then 100% take away N)

I’m fully happy with the logistics of the maths!

Until this bullshit!

So I’m calculating 8 outs on the turn
And 4 outs on the river! Easy!
Apparently it’s = .17 x .17 = 3%
Easy again! Makes sense


Wadafuk is up with my maths though?
I’m doing
39/47 to get me 83 percent!
Then the maths goes to **** with the 42/46 for the outs on the river!
And it ruins my equation!
What is going wrong and why am I?


Runner runner straight maths Quote
09-05-2024 , 02:20 PM
Work one case, say KQ. By symmetry, the probability of the other case (98) will be the same. For KQ, you have 8 possible turn cards that keep you alive, so 8/47 is the probability that you still could hit the river. On the river, assuming you hit a turn out, you now only have 4 outs, so 4/46 probability of completing the straight assuming you hit a turn out. Runner/runner KQ probability then is 8/47 x 4/46 = 32/2162 = 16/1081 = ~1.48%. The probability of the other case is the same, and the two cases are exclusive - both can never occur on the same runout, so we can add the probabilities, or equivalently multiply by 2 to get 32/1081 = ~2.96%

Your attempted strategy works better for “OR” events, like “I have 8 outs; what is the probability that I will hit one on the turn OR the river?” This case is an “AND” event — “What is the probability that I will hit one of eight outs on the turn AND one of four on the river?” No need to do the probability of the event not occurring; we can get the probability directly by multiplying the individual event probabilities.

Last edited by stremba70; 09-05-2024 at 02:30 PM.
Runner runner straight maths Quote
09-06-2024 , 03:30 PM
Thank you so much for this reply! You really helped!

If there was only one straight draw available you wouldn’t x 2 at the end right?
That’s just because of the two separate combos that could come (Kq and 89)

Thank you again
Runner runner straight maths Quote
09-09-2024 , 10:57 AM
Correct. A runner runner with only one possible combo to hit (like AT2 on the board when you have a Q and no K or J - you can only hit the straight with KJ) would be half as likely. The x2 is due to the two possible runner runner combos
Runner runner straight maths Quote

      
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