Quick maths question about odds...
Join Date: Jul 2006
Posts: 1,192
Guys,
Im not smart enough to figure this out but how does one figure out the chances out losing or winning percentages over say 3 hands in a row. For example, what are the odds that you would lose to a 10%er three times in a row?
Thanks
Join Date: Jan 2007
Posts: 357
You mean you have 90% probability to win? Then it's 0.1^3 = 0.001. (= 0.1%)
Join Date: Jan 2008
Posts: 325
Anton's right, but to clarify: 10% is the same as 0.1, and since there are three iterations, it's 0.1 * 0.1 * 0.1, or 0.1^3.
Of course, if you've already lost the first two "10%ers" and you want to know the odds of losing the third, it's still 10% (not 0.1%) because the events are independent from each other (in other words, the fact that you lost the first two 10%ers has no bearing on the outcome of the third event).
