Over the board, Black should analyze this as a straight race in which there are no gammons for either side. Black leads by 26 pips, 100 to 126.
In a cash game, this position is an easy pass. One way to see this is to add 10% + 2 pips to the leaders pip count, and round up to the nearest whole number. The result gives the final take point for the trailer. By this method, White's take point is 100 + 10 + 2 = 112. Alternatively, the more complex
Keith Count gives the same result. Adding 1/7 to the leader's count, and rounding down, gives 114. By the Keith Count, White can take when his count is 112 or less. Thus, the two racing formulas give the same take point in a money game.
Is Black too good? Probably not, because his gammon wins are so few.
Match Equity Calculations
In a match, things may be quite different. After a double and a take, White has an auto-recube, so Black must understand that when White takes, the game will be played with the cube at 8. From the Kazaross XG2 MET, we find these
Match Winning Chances (MWC) for the trailer:
Double, pass, Black wins 2: At 13-3 (2-away, 12-away), the trailer's MWC is 4.75%.
Double, take, auto-recube, Black wins 8: At 21-3, (match over), the trailer's MWC is 0%.
Double, take, auto-recube, White wins 8: At 11-11 (4-away, 4-away), the trailer's MWC is 50%.
For the trailer, the take point is found as:
Gain by taking = MWC( take, recube, win ) - MWC( pass ) = 50% - 4.75% = 45.25%
Loss by taking = MWC( pass ) - MWC( take, recube, lose ) = 4.75%
Take point = Loss / ( Gain + Loss ) = 4.75% / (45.25% + 4.75% ) = 4.75% / 50% = 9.5%
This means White can take any time his
Game Winning Chance (GWC) is better than 9.5%. My guess is that White is still better than that in this race, so Black should not double, and if doubled, White should take, and recube on the next turn.
Kleinman Count
At home, we can be a bit more precise about this. Danny Keinman gives the following technique for
estimating the GWC in a race.
Start by adding 4 pips to the leader's pip count, to take into account the fact that he is on roll.
L = 104 = leader's pip count + 4
T = 126 = trailer's pip count
D = 22 = difference = T - L
S = 230 = sum = T + L
K = 2.1 = Kleinman count = D * D / S
For K > 1.0, Øystein Johansen gives us:
GWC = 84.48% = 0.76 + 0.114 * ln(K), where ln(K) is the natural logarithm of K
As expected, Black is still way short of a double.
My solution:
No double, take, auto-recube
For the Record
I am so often wrong that I like to post my record in these messages. It's kind of a truth-in-advertising thing.
Grunch: I have been answering these problems without the use of a bot, and before checking the excellent solutions of others, since Problem 28. My record at this writing is 51%.
Last edited by Taper_Mike; 12-06-2011 at 04:02 AM.